The average atomic mass of tellurium, calculated from its eight isotopes (Te-120 (0.09%), Te-122 (2.46%), Te-123 (0.87%), Te-124 (4.61%), Te-125 (6.99%), Te-126 (18.71%), Te-128 (31.79%), and Te-130 (34.48%)) is 127.723 amu.
The average atomic mass of Te can be calculated as follows:
Where:
m: is the mass
%: is the abundance percent
Knowing all the masses and abundance values, we have:
To find the <u>average atomic mass</u> we need to change all the <u>percent values</u> to <u>decimal ones</u>
Therefore, the average atomic mass of tellurium is 127.723 amu.
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Answer:
[H⁺] = 6.083x10⁻⁴ M, [C₆H₅OO⁻] = 6.083x10⁻⁴ M, [C₆H₅OOH] = 3.98x10⁻³M, pH = 3.22
Explanation:
Data: we have 0.56 gr of benzoic acid, disolved in 1Lt of water. Kₐ = 6.4x10⁻⁵
M (molar mass) of BA (Benzoic Acid) = 122 g/mol
Then, the inicial concentration is 0.56/122 = 4.59x10⁻³ M
We should consider the equation once it reaches the equilibrium:
C₆H₅COOH ⇄ C₆H₅COO⁻ + H⁺
C - x x x
And, for the Kₐ:
Kₐ = [H⁺][C₆H₅COO⁻]/[C₆H₅COOH] = x²/(C-x) , where C = 4.59x10⁻³
Then: x² + Kₐx - KₐC = 0
x² + 6.4x10⁻⁵ - 2.9x10⁻⁷ = 0
Resolving this cuadratic equation (remember to use Baskara equation), we obtain:
x = 6.083x10⁻⁴ M
Then: [H⁺] = [C₆H₅COO⁻] = 6.083x10⁻⁴ M
[C₆H₅COOH] = C - x = 3.98x10⁻³ M
pH = -Log [H⁺] = 3.22
Answer:
C) nonmetal
Explanation:
Given;
The sample is in liquid state and do not conduct electricity.
We have given four types of classification.So for first,
A) Ionic
Ionic compounds are found in solid state at room temperature and it conducts electricity when dissolved in water. Hence the sample could not be ionic.
B)Metal
Metals are found in solid state at room temperature except mercury and it conducts electricity very well. Mercury also conducts electricity.So the sample is not a metal.
C)Nonmetal
Non metals are found in solid state except bromine which is in liquid state at room temperature and it does not conducts electricity.
Here the property of nonmetal matches with the sample, so the sample is a nonmetal and it could be Bromine.
D)Salt
Salt is an ionic compound found in solid state at room temperature and it conducts electricity when dissolved in water. Hence the sample could not be salt.
To solve this problem, we establish the general energy balance:
ΔE = ΔU + ΔKE + ΔPE
ΔE = Q + W
Q + W = ΔU + ΔKE + ΔPE
In this case, ΔKE and ΔPE are both zero or negligible.
Given:
m = 33.0 grams of CO2
Tsub = 77 K
P = 1 atm
ΔE = Q + W
ΔE = mCpΔT + ΔPV
solve for mCpΔT, find the value of Cp for CO2, then solve for Q. Next, solve for W using the ideal gas law. Add the two values and that will be the value of the delta E.
