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sammy [17]
4 years ago
14

HELP ME PLEASE!!!!!!!!!!

Chemistry
2 answers:
kobusy [5.1K]4 years ago
5 0

Answer:

the grass field I think

Explanation:

umka2103 [35]4 years ago
3 0

Answer:

I feel likes it D.....................................

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Which of the following best explains the trend in ionization energy across a period?
Alina [70]

A) It decreases because the distance between the nucleus and outermost shell increases

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Without what do carbohydrates fats and proteins can not be changed into energy
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A. Clearly draw the Lewis structure for the PBr4- ion. Show your math where
Nataliya [291]

Answer:

   Br

    |

Br-P-Br

    |

   Br

Explanation:

To calculate the valance electrons, look at the periodic table to find the valance electrons for each atom and add them together. P is in column 5A, so it has 5, Br is in column 7A, so it has 7 (multiply by 4 since there are 4 Br atoms to give 28) and there is a 1- charge, so add one more electron. 5+28+1=34, so there are 34 electrons to place. P would be the central atom, so place it in the middle. Place each Br around the P (as shown above) with a a single line connecting it. Each line represents 2 electrons, so 8 total have been place, leaving 26 remaining. Place 6 electrons around each Br (2 on each of the unbonded sides), which leaves 2 electrons remaining. The remaining pair of unbound electrons will be attached to the P between any two Br atoms. Phosphorus doesn't have to follow the octet rule, so it actually ends up with 10 valance electrons.

4 0
3 years ago
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I’m so confused somebody help lol
Marysya12 [62]

Answer:

lol☺️☺️☺️☺️☺️☺️☺️☺️

5 0
3 years ago
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Find the number of CoCl2 units present in a 0.78 mol sample.
stich3 [128]

\qquad\qquad\huge\underline{{\sf Answer}}

Here we go ~

1 mole of \sf{ COCl_2} has 6.022 × 10²³ molecules of the given compound.

So, 0.78 mole of \sf{COCl_2} will have ~

\qquad \sf  \dashrightarrow \: 0.78 \times 6.022 \times 10 {}^{23}

\qquad \sf  \dashrightarrow \:  \approx4.7 \times 10 {}^{23}  \:  \:  \: molecules

5 0
2 years ago
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