If chromium(II) iodide is dissolved in water you can say that the equilibrium concentrations of chromium(II) and iodide ions are
1 answer:
Answer:
See explanation.
Explanation:
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In this case, according to the given information, it turns out firstly necessary for us to set up the equilibrium reaction by which chromium (II) iodide is ionized as follows:
Thus, it is possible to notice that the the moles, and therefore concentrations, of chromium(II) and iodide ions are going to be different, by a factor of 2 due to the mole ratio in the aforementioned chemical equation.
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Answer:
The total pressure of the mixture in the tank of volume 6.25 litres at 51°C is 1291.85 kPa.
Explanation:
For N2,
Pressure(P₁)=125 kPa
Volume(V₁)=15·1 L
Temperature (T₁)=25°C=25+273 K=298 K
Similarly, for Oxygen,
Pressure(P₂)= 125 kPa
Volume(V₂)= 44.3 L
Temperature(T₂)=25°C= 298 K
Then, for the mixture,
Volumeof the mixture( V)= 6.25 L
Pressure(P)=?
Temperature (T)= 51°C = 51+273 K=324 K
Then, By Combined gas laws,
or,
or,
or,
∴P=1291.85 kPa
So the total pressure of the mixture in the tank of volume 6.25 litres at 51°C is 1291.85 kPa.