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11Alexandr11 [23.1K]

4 years ago

12

You guyss know it's math

1 answer:

a_sh-v [17]4 years ago

3 0

The coefficient of X is -2

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Drag each tile to the correct box. not all tiles will be used.Chris plans to mulch the border surrounding a rectangular garden i

amm1812

Length (L): 2w + 3

width (w): w

border (b): $\frac{1}{4} w$

Area (A) = (L + b) * (w + b) <em>NOTE: This is assuming the width also has a border</em>

= (2w + 3 + $\frac{1}{4} w$ ) * (w + $\frac{1}{4} w$ )

= $(2\frac{1}{4} w + 3)$ $(1\frac{1}{4} w)$

= $(\frac{9}{4} w + 3)$ $(\frac{5}{4} w)$

= $\frac{45}{16} w^2 + \frac{15}{4}w$

5 0

3 years ago

The width of rectangle A is the sum of twice a number and 8. The length of the rectangle is 3 times as great as the width. If th

Galina-37 [17]

Formula for perimeter of a rectangle = 2(L + W)
let the number be x
width = 2x + 8
length = 3(2x + 8)
substitute respectively
96 = 2 (2x + 8 + 3(2x + 8)) open the bracket
96 = 2 ( 2x + 8 + 6x + 24) collect like terms
96 = 2 (8x + 32) open the bracket
96 = 16x + 64
collect like terms
96 - 64 = 16x
32 = 16x
divide both sides by 16
32/16 = 16x/16
2 = x
therefore, the width = 2x + 8 = 2(2) + 8 = 4 + 8 = 12.
and the length = 3(2x + 8) = 6x + 24 = 6(2) + 24 = 12 + 24 = 36.

4 0

3 years ago

the diameter of a cylindrical construction pipe is 4 ft. if the pipe is 19 ft long, what s it’s volume?

STALIN [3.7K]

Answer:

76 $\pi$ or 238.76 $units^{3}$

Step-by-step explanation:

The volume of a cylinder is V = $\pi r^{2} h$

Here the radius is r = $\frac{1}{2} d$ = $\frac{1}{2}(4)=2$

The height is given as 19 ft

Then plug in all the numbers into the equation

V = $\pi (2^{2})(19) = 76\pi = 238.76 units^{3}$

4 0

3 years ago

Plzzzz help meim almost out of time thank uuuuu

Masja [62]

Answer: line 2

Explanation: hope this helps

7 0

3 years ago

Choose all the functions that give the sequence:

TEA [102]

Hence, the functions that produce given sequence are:

f(n) = 2n + 1

f(n) = 2(n − 1) + 3

Further explanation:

We will put n=1,2,3,4,5 to find which functions give the given sequence

<u>f(n) = 2n − 1</u>

Putting values of n

$f(1)=2(1)-1=2-1=1\\f(2)=2(2)-1=4-1=3\\f(3)=2(3)-1=6-1=5$

This function doesn't generate the given sequence

<u>f(n) = 2n + 1</u>

Putting values of n

$f(1)=2(1)+1=2+1=3\\f(2)=2(2)+1=4+1=5\\f(3)=2(3)+1=6+1=7\\f(4)=2(4)+1=8+1=9\\f(5)=2(5)+1=10+1=11$

This function generates the given sequence.

<u>f(n) = 2(n − 1) − 3</u>

Putting values of n

$f(1) = 2(1 -1) -3=2(0)-3=0-3=-3\\f(2) = 2(2 -1) -3=2(1)-3=2-3=-1\\f(3) = 2(3-1) -3=2(2)-3=4-3=1$

This function doesn't generate the given sequence

<u>f(n) = 2(n − 1) + 3</u>

Putting values of n

$f(1) = 2(1 - 1) + 3=2(0)+3=0+3=3\\f(2) = 2(2 - 1) + 3=2(1)+3=2+3=5\\f(3) = 2(3 - 1) + 3=2(2)+3=4+3=7\\f(4) = 2(4 - 1) + 3=2(3)+3=6+3=9$

Hence, the functions that produce given sequence are:

f(n) = 2n + 1

f(n) = 2(n − 1) + 3

Keywords: Functions, Sequence

Learn more about functions at:

#LearnwithBrainly

8 0

3 years ago