Answer:
Any numbers above -5 make this inequality true. Values that will make the inequality true: -4, -3, -2, -1, 0, 1...
Answer:
b. (2, 5, 3)
Step-by-step explanation:
Trying the offered choices seems the fastest way to find the answer. The second choice works in all equations, hence is the solution.
Another strategy you can use is to see if the equations are dependent. Here, it looks like adding twice the third equation to the other two eliminates at least the x- and y-variables. If that eliminates z, then there are infinite solutions. Instead, it gives the equation ...
7z = 21
z = 3 . . . . . divide by 7
This answer is consistent with choice B, confirming that answer and eliminating the other choices.
Answer:
Part A:
0.1111111111111 = 1/9
Part B:
3
Step-by-step explanation:
Part A:
When I put 0.111111111 into my calculator I get a conversion of 1/9.
Part B:
The fraction 1/9 means that for every 9 kids he surveyed, 1 of them replied "yes."
So covert 1/9 into x/27
27/9 = 3 which means 9 goes into 27, 3 times.
Multiply 1 by 3.
1 x 3 = 3
Put into fraction form
3/27
This means 3 students out of 27 answered "yes."
Answer:
5 1/3
Step-by-step explanation:
2 1/3+(2 2/3) (1 1/8)= 5 1/3
Answer/Step-by-step explanation:
To represent the data given on a stem and leaf plot, the whole number in a given value would be used as the stem, while the number after the decimal point is the leaf. (Key: 3|3 = 3.3).
For example, in the first stem in the first row, we have 4 as the stem. All values that starts with 4 point would be represented in this row. The digit after 4 point for each of the values would be written on the leaf column in the first row, from the least to the largest. For the first row we have: 4 | 3 9.
Same applies to the rest rows.
The stem plot would look like the one below:
Ice Thickness:
Stem | Leaf
4 | 3 9
5 | 1 8 8 8 9
6 | 5 8 9 9
7 | 0 2 2 2 2 5 9
8 | 0 7
The data of the stem-and-leaf plot shows a bell-shaped pattern with majority of the ice thickness for the 20 locations clustering around the center of the data distribution.
