There are two equations and two variables. You can solve for each variable using either the elimination method or the substitution method. Here, I believe the elimination method would be best:
5a = -4b + 5
3a = -2b + 3
You can multiply the second equation by two, so the 4b and -4b in both equations will cancel each other out when you add them. So:
5a = -4b +5
6a = 4b +6
Add both equations together.
11a = 11
a = 1
Plug in the a value into any of the previous equations:
5(1) = -4b + 5
-4b = 0
b = 0
So, since we know that b = 0, 6b is also 0.
How can we help you with this?
Answer:
J. 19.7
Step-by-step explanation:
SOH<em>(</em><em>sine = </em><em>opposite side/hypotenuse)</em> CAH TOA
sin 80° = RS/20
=> 0.985 = RS/20
=> RS = 20 × 0.985 = 19.7
Answer:
( J - 6 ) × (J + 6 )
Step-by-step explanation:
j^2 -6^2
( J - 6 ) × ( j + 6 )
