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hram777 [196]
3 years ago
14

Solve this system of linear equations. Separate

Mathematics
1 answer:
dmitriy555 [2]3 years ago
8 0

Answer: x= -2 and y=7

Step-by-step explanation:

4×20x+11y=37

20×4x+3y=13

Using elimination method

80x+44y=148

80x+60y=260

-16y/-16=-112/-16

Y=7

Substitute for Y in equation (1)

20x+ 11(7)=37

20x+77=37

20x=37-77

20x/20= -40/20

X= -2

therefore, x=-2 and y=7

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audrey has 32 dimes and quarters in her piggy bank with a total value of $6.50. how many of the coins are dimes and how many are
AfilCa [17]
22 quarters= $5.50
10 dimes= $1.00

$5.50 + $1.00 = $6.50
I just did trial and error. I started with 20 quarters and made changes until it worked.

4 0
3 years ago
Question 31 (Essay Worth 5 points)
slega [8]

Answer:

-12

Step-by-step explanation:

ds/dt = d/dt ( 1-12 t)

ds/dt = -12

When t=2

ds/dt = -12

7 0
3 years ago
Nine less than a number is no more than 8 and is no less than 3
frozen [14]

9 - x < 8 => -x < 8 - 9 => -x < -1 => x > 1

9 - x > 3 => -x > 3 -9 => -x > -6 => x < 6

So the number is between 1 and 6, notation 1 < x < 6

7 0
4 years ago
The length of a rectangle is seven times its width. The area of the rectangle is 175 square centimeters. Find the dimensions of
dimulka [17.4K]

Answer:

<h3>The length is 35cm</h3><h3>The width is 5cm</h3><h3 />

Step-by-step explanation:

Area of a rectangle = l × w

where

l is the length

w is the width

The length is seven times the width is written as

l = 7w

Area of the rectangle = 175 cm²

7w × w = 175

7w² = 175

Divide both sides by 7

w² = 25

Find the square root of both sides

w = √25

w = 5cm

But l = 7w

l = 7(5)

l = 35cm

The length is 35cm

The width is 5cm

Hope this helps you.

7 0
3 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
wel

Answer:

z=\frac{15\sqrt{3}}{2}

Step-by-step explanation:

In leftmost triangle:

opposite side =y

adjacent=a

now, we can use trig formula

tan(60)=\frac{y}{a}

now, we can solve for y

y=atan(60)

In rightmost triangle:

adjacent=b

opposite=y

a+b=15

b=15-a

now, we can use trig formula

tan(30)=\frac{y}{15-a}

now, we can solve for y

y=(15-a)tan(30)

now, we can set them equal

and then we can solve for a

atan(60)=(15-a)tan(30)

\sqrt{3}a\cdot \:3=\frac{\sqrt{3}\left(15-a\right)}{3}\cdot \:3

4\sqrt{3}a=15\sqrt{3}

a=\frac{15}{4}

now, we can find b

b=15-\frac{15}{4}

b=\frac{45}{4}

now, we can use trig formula

cos(30)=\frac{b}{z}

now, we can find z

z=\frac{\frac{45}{4}}{cos(30)}

we can simplify it

and we get

z=\frac{15\sqrt{3}}{2}


4 0
3 years ago
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