A = a^2.....where " a " is the length of one side
A = 79
79 = a^2...take sqrt of both sides, eliminating the ^2
sqrt 79 = a
8.89 = a
so the length of one side is approximately 8.89 ft <==
Answer:
Affects the width of a confidence interval, as the margin of error is a function of the sample standard deviation.
Step-by-step explanation:
When we have the standard deviation for the sample, the t-distribution is used to solve the question.
It does not affect the center of the interval, which is a function only of the sample mean.
Width of a confidence interval:
The width of a confidence interval is a function of the margin of error, which is:

In which s is related to the sample standard deviation. Thus, since s and M are directly proportional, a higher standard deviation makes the interval wider, lower standard deviation makes the interval narrower, and thus, the sample standard deviation affects the the width of a confidence interval.
Answer:
Ok, and it's 9.35423007
Step-by-step explanation:
Answer:
The second one, the second to last one, and the last one.
Step-by-step explanation:
The second one is negative because if you add a negative number with a positive number it becomes negative.
The second to last one is zero because if you add a negative and a positive number that is the same number then it becomes zero.
And the last one, they are both simply positive.
Hope this helps <3
Answer:
1 55
2 130
3 15
Step-by-step explanation: