Answer:
for the perimeter to be made into a equation it would take the equation
2(3x - 5) + 2(2x + 1)
And for the perimeter to equal 42 x would have to equal 5
Step-by-step explanation:
so first of all we have to find our equation to equal 42:
2(3x - 5) + 2(2x + 1) = 42
you then multiply 2 for both parentheses:
(3x * 2) + (-5 * 2) + (2x * 2) + (1 * 2) = 42
so its now:
6x -10 + 4x + 2 = 42
now your going to add variables to variables and numbers to numbers:
(6x + 4x) + ( -10 + 2) = 42
to get:
10x + (-8) = 42
Now your going to add 8 to both sides:
10x + (-8) = 42
+8 +8
Giving the equation:
10x = 50
now you divide both sides by 10 to get:
10x/ 10 = 50/10
x = 5
to solve you put 5 in place of the variable x:
2(3*5 - 5) + 2(2*5 + 1)
2(15 - 5) + 2(10 + 1)
20 + 22 = 42
So x equals 5 if the perimeter equaled 42
Actually Welcome to the Concept of the Similar Triangles.
Since here we can see that, similar triangles different by size of the side by 0.5 ration,
hence,the value of x = 0.5 times of MN
hence, x = 5/2
so the mixed fraction representation is given as,
mixed fraction ration is 2(1/2)
===> hence option is B.)
Answer
In 1 meter cubed is 1000000 centimeters cubed.
1 centimeters cubed is equal to 1.0E-6 cubic meter.
The answer is 0.25
Step-by-step explanation:
I did math.
You have 0.15 + 0.36 just like you would just add normal so 1. Would be 0.51 and the other one would be 0.15
Since you haven't provided the data to answer the problem, I have my notes here that might guide you solve the problem on your own:
Now, consider a triangle that’s graphed in the coordinate plane. You can always use the distance formula, find the lengths of the three sides, and then apply Heron’s formula. But there’s an even better choice, based on the determinant of a matrix.
Here’s a formula to use, based on the counterclockwise entry of the coordinates of the vertices of the triangle
(x1<span>, </span>y1), (x2<span>, </span>y2), (x3<span>, </span>y3<span>) or (2, 1), (8, 9), (1, 8): </span>A<span> = </span>x1y2<span> + </span>x2y3<span> + </span>x3y1<span> – </span>x1y3<span> – </span>x2y1<span> – </span>x3y2<span>.</span>