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katen-ka-za [31]
3 years ago
15

Question 31 (Essay Worth 5 points)

Mathematics
1 answer:
slega [8]3 years ago
7 0

Answer:

-12

Step-by-step explanation:

ds/dt = d/dt ( 1-12 t)

ds/dt = -12

When t=2

ds/dt = -12

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Ill give brainliest
Lera25 [3.4K]

Answer:

Change: subtract old value from new value. Example: You had 5 books, but now have 7. The change is: 7−5 = 2. Percentage Change is all about comparing old to new values.

Step-by-step explanation:

hope this helps :)

8 0
3 years ago
Read 2 more answers
The perimeter of a rectangle must be less than 156 feet. If the length is known to be 66 feet, find the range of possible widths
balu736 [363]

x = perimeter

x<156

length = 66

so, in order to calculate perimeter you need to add two lengths and two widths

so

156 (perimeter) - 2 (66) = two widths

156 - 132 = 24 (remember this number is two widths added together)

so 24 twice the width SO 12 would be the number that the width can't be larger than

the width has to be less than 12

w < 12

5 0
3 years ago
Let <img src="https://tex.z-dn.net/?f=K" id="TexFormula1" title="K" alt="K" align="absmiddle" class="latex-formula"> be a circle
yan [13]

The bisector of angle APQ passes through O and this is illustrated below.

<h3>How to illustrate the information?</h3>

From the information given, the center is O. and the circle passes through O and cuts at K.

In this case, it should be noted that the circles are equal according to the SAS test.

Here, AOB + APQ = 180° (Linear pair)

2AOB = 180

AOB = 90.

Therefore, the bisector of angle APQ passes through O.

Learn more about bisector on:

brainly.com/question/11006922

#SPJ1

8 0
2 years ago
Find area and perimeter of shaded regions below
aleksandrvk [35]

Answer:

Step-by-step explanation:

ABCD is a square.

side = 24 cm

Area of square = side  * side = 24 * 24 = 576 cm²

Semicircle:

d = 24 cm

r = 24/2 = 12 cm

Area of semi circle =πr²

                               = 3.14 * 12 * 12

                               = 452.16 cm²

Area of shaded region = area of square - area of semicircle  + area of semicircle

  = 576  - 452.16 + 452.16

  = 576 cm²

Perimeter:

Circumference of semicircle = 2πr

               = 2 * 3.14 * 12

               = 75.36

Perimeter = 2* circumference of semicircle + 24 + 24

                = 2 * 75.36 + 24 + 24

                = 150.72 + 24 + 24

                 = 198.72 cm

6 0
3 years ago
What is an equation of the line that passes through the points ( 0,-7) and ( 5, -1)
tresset_1 [31]

Answer:

y = 5/6x - 5.167

Or

y = 5/6x - 31/6

Step-by-step explanation:

The equation of a line

y = mx + c

Step 1: find the slope

m = y2 - y1 / x2 - x1

Given points

( 0 , -7) ( 5 , -1)

x1 = 0

y1 = -7

x2 = 5

y2 = -1

Insert the values into the equation

m = -1 - (-7) / 5 - 0

m = -1 + 7 / 5

m = 6/5

y = 6/5x + c

Step 2: sub any of the two points given into the equation

y = 5/6x + c

( 5 , -1)

x = 5

y = -1

-1 = 5/6(5) + c

-1 = 5*5/6 + c

-1 = 25/6 + c.

c = -1 - 25/6

LCM = 6

c = -6 - 25 / 6

c = -31/6

c = -5.167

Step 3: sub c into the equation

y = 5/6x + c

y = 5/6x - 31/6

Or

y = 5/6x - 5.167

The equation of the line is

y = 5/6x - 5.167

7 0
3 years ago
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