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3 years ago

What is the answer. plz heelp 5h+2(11-h)= -5

Mathematics

1 answer:

aliya0001 [1]3 years ago

4 0

Answer:

h = -9

Step-by-step explanation:

5h+2(11-h)= -5

Distribute

5h +22 -2h = -5

Combine like terms

3h +22 = -5

Subtract 22 from each side

3h +22-22 = -5-22

3h = -27

Divide by 3

3h/3 = -27/3

h = -9

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Brown rice costs $2 per pound, and beans cost $1.60 per pound. Lin has $10 to spend on these items to make a large meal of beans

Valentin [98]

Answer:

1. $2r+1.6b=10$

2. $r=5-0.8b$

3. $b=6.25-1.25r$

Step-by-step explanation:

<h3> The complete exercise is: "Brown rice costs $2 per pound, and beans cost $1.60 per pound. Lin has $10 to spend on these items to make a large meal of beans and rice for a potluck dinner. Let b be the number of pounds of beans Lin buys and r be the number of pounds of rice she buys when she spends all her money on this meal.</h3><h3>1. Write an equation relating the two variables.</h3><h3>2. Rearrange the equation so "b" is the independent variable.</h3><h3>3. Rearrange the equation so "r" is the independent variable."</h3><h3 />

1. According to the information exercise given in the exercise, the cost per pounds of brown rice is $2. Since "r" represents the number of pounds of rice Lin buys, the total cost of the brown rice she buys can be represented with this expression:

$2r$

The beans cost $1.60 per pound. Since "b" represents the number of pounds of beans Lin buys, the total cost of beans she buys can be represented as:

$1.6b$

Knowing that she spends $10, you can write the following equation:

$2r+1.6b=10$

2. In order to rearrange the equation so "b" is the independent variable, you need to solve for "r":

$2r+1.6b=10\\\\2r=10-1.6b\\\\r=\frac{10-1.6b}{2} \\\\r=5-0.8b$

3. To rearrange the equation so "r" is the independent variable, you must solve for "b". You get:

$2r+1.6b=10\\\\1.6b=10-2r\\\\b=\frac{10-2r}{1.6}\\\\b=6.25-1.25r$

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3 years ago

Please Help? The volume of a cylinder is 176pi cm.square and its height is 11cm. What is the length of the cylinder radius?

timofeeve [1]

Answer:

Step-by-step explanation:

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4 years ago

Mark records his science scores in each monthly assessment over a period of 5 months. In the first assessment he scores 76%. In

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This is the complete question:

Mark records his science scores in each monthly assessment over a period of 5 months. In the first assessment he scores 76%. In the second assessment he scores 73%. After that, his scores keep increasing by 2% in every assessment. Assume that x represents the number of assessments since he starts recording and y represents the scores in each assessment, which of the following describes the situation?

a. a relation only b.

b. neither a function nor a relation

c. a function only

d. both a relation and a function

Answer:

<u><em>d. both a relation and a function</em></u>

Step-by-step explanation:

<em>A relation</em> is any statement, either verbal or mathematical, that connects, interrelates or associates, two or more elements (objects, persons, variables).

The text describes a situation where the scores in the assesments are related to the number of statements since Mark starts recording, hence this is a relation.

<h2>Is this relation a function or not?</h2>

In order for a relation be a function, the association has to be unambiguos. This means that for a given input only one output can exist. If an input can have two or more outputs, then you can not determine which is the output for that input. This is what defines whether a relation is a function or not.

In the situation described in the text, x is the input, i.e. the number of assessments since Mark starts recording the scores. Definetely, the number of assessment is not repeated: there is only one first assessment, only one second assessment, only one third assessment, ... the number of assessment cannot not get repeated. Of course, if the input is not repeated, there is only one output associated to the input (each assessment has just one associated score) and the relation is a function.

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Ilia_Sergeevich [38]

Answer:

The seconf option

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Step-by-step explanation:

plug in your x and y points into the equation and they should be the same of both sides

ex (0,3)

3 = 0 + 3

^y ^x

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