Answer:
Step-by-step explanation:
You haven't given us a diagram of your figure. Assume it is like the one in the image below.
The formula for the area of a parallelogram is
A = bh
1. Determine the height of the parallelogram
Notice that the angle is 45°. That makes the triangle an isosceles right triangle, so we can use Pythagoras' Theorem.
h² + h² = (6√2)²
2h² = 36 × 2 = 72
h² = 36
h = 6
2. Calculate the area of the parallelogram
<h3>
Explanation:</h3>
<em>no solution</em>. An absolute value cannot be negative.
The three vectors 
, 
, and 
each terminate on the plane. We can get two vectors that lie on the plane itself (or rather, point in the same direction as vectors that do lie on the plane) by taking the vector difference of any two of these. For instance,
Then the cross product of these two results is normal to the plane:
Let 
be a point on the plane. Then the vector connecting to a known point on the plane, say (0, 0, 1), is orthogonal to the normal vector above, so that
which reduces to the equation of the plane,
Let 
. Then the volume of the region above 
and below the plane is
The ratio of heights = ratio of the square roots of the areas because area is 2 dimensional and height is one dimensional.
so required ratio is sqrt 40pi : = sqrt40:sqrt80 = sqrt1: sqrt2 = sqrt (1/2) = 0.7071 to 4 significant figures
It would be 5 tens + 4 tens = 9 tens
