Help please thank you

A polynomial has been factored below, but some constants are missing. 2x^3 –6x^2 –8x=ax(x+b)(x+c) What are the missing values of

Anarel [89]

2x (x - 4) (x + 1). A=2, B=-4, C=1

7 0

3 years ago

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Victoria whit used 578 kw-hr of electricity in December the rate is 9.1 cents per kw-hr find the amount of her electric bill

MatroZZZ [7]

Answer:

The amount of electricity bill is <u>$52.60</u>.

Step-by-step explanation:

Given:

Victoria whit used 578 kwh of electricity.

The rate is 9.1 cents per kw-hr.

Now, to find the amount of her electric bill.

Electricity used = 578 kwh.

Rate of electricity = 9.1 cents per kw-hr.

So, to get the amount we multiply the electricity used by the rate of electricity:

$Amount\ of\ electric\ bill=Electricity\ used\times rate\ of\ electricity$

$Amount\ of\ electric\ bill=578\ kwh\times 9.1\ cents$

$Amount\ of\ electric\ bill=5259.8\ cents.$

Thus, the amount of electricity bill = 5259.8 cents.

Now, converting the amount from cents to $ by dividing:

$1 = 100 cents.

So, 5259.8 cents ÷ 100 = $52.60 .

therefore, the amount of electricity bill is $52.60.

3 0

3 years ago

Which of the following graphs could represent a cubic function?

xeze [42]

Answer:

A

Step-by-step explanation:

Here, we want to select which of the graph represents a cubic equation

Graphs B and C looks parabolic and thus, they probably will represent a quadratic equation

Graph D represents a straight line equation

Graph A represents a cubic function due to its shape

So our answer is graph A only

8 0

3 years ago

SOMEONE PLEASE HELP ME ANSWER QUESTION 7

zlopas [31]

Hope it helps!!!!!!!!!

7 0

4 years ago

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Dada a função f(x) = ax + b e sabendo-se que f(3) = 5 e f(-2) = -5 calcule f(½)

d1i1m1o1n [39]

Answer:

$f(1/2)=0$

Step-by-step explanation:

Given this function:

$f(x)=ax+b$

We need to find the value of:

$f(1/2)$

This is really simple because the problem give us the following data:

$f(3)=5\\\\and\\\\f(-2)=-5$

Using this data we can write a 2x2 system of equations like this:

Let:

$f(3)=5=a(3)+b\\\\\rightarrow3a+b=5\hspace{10}(1)$

and

$f(-2)=5=a(-2)+b\\\\\rightarrow-2a+b=-5\hspace{10}(2)$

Our system will be:

$3a+b=5\hspace{28}(1)\\-2a+b=-5\hspace{10}(2)$

We can solve this system using different methods, however I will use elimination method because I believe it is really simple. So:

$(1)-(2)\\\\5-(-5)=3a-(-2a)+b-b\\\\10=5a\\\\Solving\hspace{3}for\hspace{3}a\\\\a=\frac{10}{5} =2$

Replacing $a$ into (1)

$3(2)+b=5\\\\6+b=5\\\\Solving\hspace{3}for\hspace{3}b\\\\b=5-6=-1$

Now we found the values of $a$ and $b$ , our function is given by:

$f(x)=2x-1$

Let's verify it:

$f(3)=2(3)-1=6-1=5$

$f(-2)=2(-2)-1=-4-1=-5$

As you can see the function satisfies the data provided by the problem. So we can conclude that it is correct.

Finally, let's find $f(x)$ for $x=1/2$ :

$f(1/2)=2(\frac{1}{2} )-1=\frac{2}{2} -1=1-1=0$

Hence:

$f(1/2)=0$

3 0

4 years ago