Answer:
Let's simplify step-by-step.
(3)(3)−(19)(2)+kx−30
=9+−38+kx+−30
Combine Like Terms:
=9+−38+kx+−30
=(kx)+(9+−38+−30)
=kx+−59
Answer:
=kx−59
From Left side:
NOTE: sin²θ + cos²θ = 1
Left side = Right side <em>so proof is complete</em>
Answer:
If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.
Step-by-step explanation:
Here in this question, we want to state what will happen if the null hypothesis is true in a chi-square test.
If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.
This is because at a higher level of discrepancies, there will be a strong evidence against the null. This means that it will be rare to find discrepancies if null was true.
In the question however, since the null is true, the discrepancies we will be expecting will thus be small and common.
Answer:
length = 20cm
breadth = 8cm
Step-by-step explanation:
solution;
length(l) = x + 12
breadth(b) = x
perimeter (p) = 56 cm
we know that,
perimeter(p) = 2(l + b)
or, 56 = 2(x + 12 + x)
or, 56 = 2(2x + 12)
or, 56 = 4x +24
or, 56 - 24 = 4x
or, 32 = 4x
or, 32 / 4 = x
x = 8
now
putting the value of x in length and breadth
length = x+ 12
=8 + 12
=20cm
breadth = 8cm
Start with the brackets. Then do 5 multiply 1 which is 5 then divide that 5 from 20 which gets you 4. Times the outside of the brackets with the inside which will give you the answer of 16
