Answer:
The probability of observing a sample mean of 31.1 grams of fat per pound or less in a random sample of 34 farm-raised trout is 0.227
Step-by-step explanation:
Let X be the sample mean of fat in 34 farm-raised trout
The probability of observing a sample mean of 31.1 grams of fat per pound or less in a random sample of 34 farm-raised trout can be stated as:
P(X<31.1 grams) = P(z<z*)
where z* is the z-statistic of sample mean of 31.1 grams fat.
z* can be calculated as follows:
z*=
where
- M is the average grams of fat per pound (32)
- s is the standard deviation (7)
- N is the sample size (34)
Then z*=
≈ −0.7497
and P(z<z*) ≈ 0.227
The probability of observing a sample mean of 31.1 grams of fat per pound or less in a random sample of 34 farm-raised trout is 0.227
Answer:
Unique solution
Step-by-step explanation:
Given
![3x+4y+2=0](https://tex.z-dn.net/?f=3x%2B4y%2B2%3D0)
![4x-5y+13=0](https://tex.z-dn.net/?f=4x-5y%2B13%3D0)
Required
The type of solution
A linear equation is represented as:
![Ax + Bx + C =0](https://tex.z-dn.net/?f=Ax%20%2B%20Bx%20%2B%20C%20%3D0)
For the first equation:
![A_1 = 3\ B_1 = 4\ C_1 = 2](https://tex.z-dn.net/?f=A_1%20%3D%203%5C%20B_1%20%3D%204%5C%20C_1%20%3D%202)
For the second:
![A_2 = 4\ B_2 = -5\ C_2 = 13](https://tex.z-dn.net/?f=A_2%20%3D%204%5C%20B_2%20%3D%20-5%5C%20C_2%20%3D%2013)
We have:
![\frac{A_1}{A_2} = \frac{3}{4}](https://tex.z-dn.net/?f=%5Cfrac%7BA_1%7D%7BA_2%7D%20%3D%20%5Cfrac%7B3%7D%7B4%7D)
![\frac{B_1}{B_2} = -\frac{4}{5}](https://tex.z-dn.net/?f=%5Cfrac%7BB_1%7D%7BB_2%7D%20%3D%20-%5Cfrac%7B4%7D%7B5%7D)
By comparison:
![\frac{A_1}{A_2} \ne \frac{B_1}{B_2}](https://tex.z-dn.net/?f=%5Cfrac%7BA_1%7D%7BA_2%7D%20%5Cne%20%5Cfrac%7BB_1%7D%7BB_2%7D)
<em>Hence, the system has a unique solution.</em>
Answer:
2 graphs represent a linear relationship
Step-by-step explanation:
2 out of your 3 graphs make a straight line if you were to draw a line throught the points
Answer:
The value of x and y is ,
x =
and y = 2
Step-by-step explanation:
The given two linear equation can be written as ,
y + 9x = -13 ....1 and
y - 3x = 7 .....2
Put the value of y from eq 1 into eq 2
i.e (-13 -9x) - 3x = 7
or, -12x = 7 +13
Or, -12x = 20
i.e X =
Now put t his value of x in any above two linear equation
Let put this value on eq 2 to get value of y
so its can be writen as.
y = 3x + 7
or, y = 3(
) + 7
or, y = -5 +7
i.e Y = 2
Hence the value of x and y is , x =
and y = 2 Answer