The circumference of the outer edge of the path around the pool is 113.04 ft.
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What is the circumference?</h3>
The Circumference (or) perimeter of circle = 2πR. where, R is the radius of the circle.
Given
A circular swimming pool has a radius of 15 ft.
There is a path all the way around that pool that is three feet wide.
A circle has a radius of 15 feet.
A larger circle goes around the smaller circle that is 3 feet wide.
The radius of the outer edge of the path around the pool = Radius of circle + width of outer circle.
The radius of the outer edge of the path around the pool = 15 + 3
The radius of the outer edge of the path around the pool = 18ft
The circumference of the outer edge of the path around the pool is;

Hence, the circumference of the outer edge of the path around the pool is 113.04 ft.
To know more about circumference click the link given below.
brainly.com/question/5023328
Answer:
In the episode pertaining to the discovery of radium, it is false that all of the hypotheses turned out to be true.
There are some hypotheses in the episode thay turned out to be false.
Answer:
1/3
Step-by-step explanation:
You express the values in which the teacher or tutor or whatever assigned you.
Answer:
y = 2/3x+1/3
Step-by-step explanation:
2x−3y+1 = 0
Solve for y
Add 3y to each side
2x−3y+1 +3y= 0+3y
2x +1 = 3y
Divide by 3
2/3 x + 1/3 =3y/3
2/3x +1/3 = y
The slope is 2/3 and the y intercept is 1/3
y = 2/3x+1/3