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ra1l [238]
4 years ago
14

A rectangle's perimeter is 92 ft. Its length is 5 ft shorter than two times of its width. Use an equation

Mathematics
1 answer:
Setler79 [48]4 years ago
3 0
2 x ( 2w - 5 ) + 2 x w = 92
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A yogurt costs 55 pence how many yogurts can be bought for 6 pounds?
scoray [572]
1 pound = 100 pence therefore 600 pence
600/55= 10.9
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3 years ago
Solve square root of x + square root of x+2 = 2
andrew-mc [135]

The value of x is \frac{1}{4}

Step-by-step explanation:

Given:

\sqrt{x} +  \sqrt{x + 2} = 2

Rearranging the radical on left side,

\sqrt{x + 2} = 2 - \sqrt{x}

Power on both sides,

(\sqrt{x + 2})^{2}  = (2 - \sqrt{x})^{2}

Simplifying the left,

x + 2 = (2 - \sqrt{x} )^{2}

For the RHS equation, use the property of (a-b)² = (a²-2ab+b²),

=  > x + 2 =  {2}^{2} - (2 \times 2 \sqrt{x}) + ( \sqrt{x})^{2}

Now calculating its powers,

=  > x + 2 = 4 - 4\sqrt{x} + x

Now sending -4√x to the LHS (left side), its sign becomes plus (+),

=  > 4 \sqrt{x} = 4 + x - x - 2

Now the +x and -x will be cancelled,

=  > 4 \sqrt{x} = 4 - 2

=  > 4 \sqrt{x} = 2

Bringing 4 to the right side, it becomes the denominator,

=  >  \sqrt{x} =  \frac{2}{4}

=  >  \sqrt{x} =  \frac{1}{4}

Now powering both sides,

=  > ( \sqrt{x})^{2} = ( \frac{1}{2})^{2}

=  > x =  \frac{1}{4}

4 0
3 years ago
Find the least number that must be added to 1400 so as to get a perfect squre. full explanation​
Dmitriy789 [7]

Answer:

so what is the next perfect square after 1400?  That's what they are asking.. so I used my calculator to find it..

Step-by-step explanation:

the square root of 1400= 37.41..... but since we want a perfect square.. take 38 squared.. which is  1444 so now we know.. to add 44 to 1400 .... that's your answer  44

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3 years ago
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what happen do you what to tlak

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3 years ago
How do you order two numbers written in scientific notation?
kondor19780726 [428]
This should be the answer to the problem I would explain it in my own words but it would be easier to understand if you saw it from here. I hope this helps!!

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3 years ago
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