Answer:
Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Step-by-step explanation:
We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.
<em>Firstly, Let X = diameters of ball bearings</em>
The z score probability distribution for is given by;
Z =
~ N(0,1)
where,
= mean diameter = 106 millimeters
= standard deviation = 4 millimeter
Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)
P(X > 111) = P(
>
) = P(Z > 1.25) = 1 - P(Z
1.25)
= 1 - 0.89435 = 0.1056
Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Make it an improper fraction by multiplying the whole number by the denominator then adding the numerator then find the common denominator (remember what you do to the bottom, you do to the top) then subtract normally.
eg. 1 4/5 - 1 7/10
= 9/5 - 17/10
= 18/10 - 17/10
= 1/10 or 0.1
Hope this helps!
The length and the width of the rug having an area of 40 square feet will be 5 feet and 8 feet respectively.
<h3>what is area?</h3>
Area is defined as the space covered by any object in the two dimensional plane. Here it is given that the area of the rug should be 40 square feet and the length of the rug is 3 less then its width.
So to find out the length and the width we will form an equation.
Let the width is = x feet
So the length will be = x-3 feet
Now the area will be


By solving the quadratic equation




Here the value of x will be positive because length cant be negative.
So the width of the rug will be x=8 feet
Length of the rug will be x-3= 8-3=5 feet
Hence the length and the width of the rug having an area of 40 square feet will be 5 feet and 8 feet respectively.
To know more about area follow
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Answer:
x≤5
Step-by-step explanation:
-10(9-2x)-x≤2x-5
-90+20x-x≤2x-5
19x-2x≤90-5
17x≤85
x≤85/17
x≤5
Answer:
25
Step-by-step explanation:
trust me it's right it might be easier if you use paoer