Answer:
No
Reasoning:
If something is a perfect cube, it is able to be put under a cube root (![\sqrt[3]{..}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B..%7D) ) and will result in an integer (a non-decimal number > 0, basically).
) and will result in an integer (a non-decimal number > 0, basically). 
So let's calculate ![\sqrt[3]{48}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B48%7D) , and see if the result is an integer.
, and see if the result is an integer.
![\sqrt[3]{48}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B48%7D) = 3.634.......
 = 3.634....... 
As you can see, the result is not an integer, therefore 48 is not a perfect cube.
 
        
             
        
        
        
Answer: 11) 1/3
12)1/4
13) Likely
Step-by-step explanation:
 
        
                    
             
        
        
        
Answer:
Step-by-step explanation:
3/8 miles long, 1/48 miles per hour
3/8 and 1/48 can have a common denominator, so you make 3/8 into 18/48 by multiplying both the numerator and denmoinator by 6. 
18/48 miles long
1/48 per hour
divide: 18/48 divided by 1/48, which turns into 18/48 x 48/1 which equals 18
18 hours
 
        
             
        
        
        
50:
40 is 10 less than 50
60 is 10 more than 50