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2 years ago

A number decreased by 5 is less than 33.

Mathematics

1 answer:

kozerog [31]2 years ago

5 0

Step-by-step explanation:

ket the number be x

Decreased by 5 means x-5

Less than 33 means x - 5 < 33

x < 33 + 5

x < 38

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Find the value of y...

soldier1979 [14.2K]

Answer:

y=0

Step-by-step explanation:

Rewrite Evaluate Powers:

3 $3^{2y-1}+3^{-1}+2*3^{y}*3^{-1}=1$

Calculate:

$(3^{y})^{2}*\frac{1}{3} +2*3^{y}*\frac{1}{3}=1$

Solve using substitution:

$(3^{y})^{2}*\frac{1}{3} +\frac{2}{3} *3^{y}=1$ $t=3^{y}$

Solve the equation for t:

$t^{2}*\frac{1}{3}+\frac{2}{3}t=1$

t=-3

t=1

Substitute back to t=3^y

3^y=-3

3^y=1

y∉R

$3^{y}=1$

y=0

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3 years ago

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3 years ago

If f(x)=x^2 and g(x)=1÷2x+3 find g(f(-1))

gogolik [260]

ANSWER

$g(f( - 1)) = \frac{1}{5 }$

EXPLANATION

The given function is:

$f(x) = {x}^{2}$

and

$g(x) = \frac{1}{2x + 3}$

$g(f(x)) = g( {x}^{2} )$

$g(f(x)) = \frac{1}{2{x}^{2} + 3 }$

To find g(f(-1)), we substitute x=-1, to obtain;

$g(f( - 1)) = \frac{1}{2{( - 1)}^{2} + 3 }$

We simplify the square in the denominator to get,

$g(f( - 1)) = \frac{1}{2+ 3 }$

We now add the denominator to obtain;

$g(f( - 1)) = \frac{1}{5 }$

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