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MaRussiya [10]
4 years ago
10

Kerrie is tiling the floor of a kitchen. The kitchen floor measures 11.3 feet by 9.25 feet. She orders enough tiles for 99 squar

e feet. Which statement about the amount of the tiles is correct?
Mathematics
2 answers:
Tema [17]4 years ago
6 0

This question is not complete

Complete Question

Kerrie is tiling the floor of a kitchen. The kitchen floor measures 11.3 feet by 9.25 feet. She orders enough tiles for 99 square feet. Which statement about the amount of tiles is correct?

a) Kerrie estimated correctly by rounding down. She has enough tile. The exact area is 104.5 square feet.

b) Kerrie estimated correctly by rounding up. She has enough tile. The exact area is 104.5 square feet.

c) Kerrie did not estimate correctly by rounding up. She does not have enough tile. The exact area is 104.5 square feet.

d) Kerrie did not estimate correctly by rounding down. She does not have enough tile. The exact area is 104.5 square feet.

Answer:

a) Kerrie estimated correctly by rounding down. She has enough tile. The exact area is 104.5 square feet.

Step-by-step explanation:

In mathematics we have what is defined as rounding up and rounding down.

Rounding up of numbers is when the number you want to round up is followed by number from 5 to 9(5, 6, 7, 8, 9)

E.g. 2.5 rounded up to the nearest whole number = 3

Rounding down of numbers is when the number you want to round up is followed by number from 1 to 4(1, 2, 3, 4)

E.g. 2.4 rounded down = 2

We are told in the question

Kerrie is tiling the floor of a kitchen. The kitchen floor measures 11.3 feet by 9.25 feet. She orders enough tiles for 99 square feet.

Kitchen floor is rectangular = Area = Length × Width

= 11.3 × 9.25 feet

= 104.525 square feet

We are told that Kerrie ordered for 99 square tiles.

But looking at the decimal, the number after the decimal are between 1 and 4.

Hence, she would be rounding down.

If Kerrie rounds down to the nearest whole number

11.3 feet = 11 feet

9.25 feet = 9 feet

Finding the area = 11 feet × 9 feet

= 99 square feet

Therefore, the correct statement = option a) Kerrie estimated correctly by rounding down. She has enough tile. The exact area is 104.5 square feet.

mr_godi [17]4 years ago
3 0

Answer:

104.05

Step-by-step explanation:

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SUMMARY:

x^4+\frac{5}{x^3}-\sqrt{x}+8                               →    Not a Polynomial

-x^5+7x-\frac{1}{2}x^2+9                           →    A Polynomial

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\left|x\right|^2+4\sqrt{x}-2                                   →    Not a Polynomial

x^3-4x-3                                        →    A Polynomial

\frac{4}{x^2-4x+3}                                              →    Not a Polynomial

Step-by-step explanation:

The algebraic expressions are said to be the polynomials in one variable which consist of terms in the form ax^n.

Here:

n = non-negative integer

a = is a real number (also the the coefficient of the term).

Lets check whether the Algebraic Expression are polynomials or not.

Given the expression

x^4+\frac{5}{x^3}-\sqrt{x}+8

If an algebraic expression contains a radical in it then it isn’t a polynomial. In the given algebraic expression contains \sqrt{x}, so it is not a polynomial.

Also it contains the term \frac{5}{x^3} which can be written as 5x^{-3}, meaning this algebraic expression really has a negative exponent in it which is not allowed. Therefore, the expression x^4+\frac{5}{x^3}-\sqrt{x}+8 is not a polynomial.

Given the expression

-x^5+7x-\frac{1}{2}x^2+9

This algebraic expression is a polynomial. The degree of a polynomial in one variable is considered to be the largest power in the polynomial. Therefore, the algebraic expression is a polynomial is a polynomial with degree 5.

Given the expression

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi

in a polynomial with a degree 4. Notice, the coefficient of the term can be in radical. No issue!

Given the expression

\left|x\right|^2+4\sqrt{x}-2

is not a polynomial because algebraic expression contains a radical in it.

Given the expression

x^3-4x-3

a polynomial with a degree 3. As it does not violate any condition as mentioned above.

Given the expression

\frac{4}{x^2-4x+3}

\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

Therefore, is not a polynomial because algebraic expression really has a negative exponent in it which is not allowed.

SUMMARY:

x^4+\frac{5}{x^3}-\sqrt{x}+8                               →    Not a Polynomial

-x^5+7x-\frac{1}{2}x^2+9                           →    A Polynomial

x^4+x^3\sqrt{7}+2x^2-\frac{\sqrt{3}}{2}x+\pi              →    A Polynomial

\left|x\right|^2+4\sqrt{x}-2                                   →    Not a Polynomial

x^3-4x-3                                        →    A Polynomial

\frac{4}{x^2-4x+3}                                              →    Not a Polynomial

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