-π/2 < arctan(x) < π/2
So cos(π/2) < cos(arctan(x)) < cos(0)
0 < cos(arctan(x)) < 1
That question is impossible because we don’t know what we are trying to solve for it has to be x or y in this scenario it can’t be both we need one to find the other
The problem is an arithmetic sequence with:
a₁ = 206,300
an = 208,400
n = 2013 - 2000
n = 13
To find the annual increase, use this following formula
an = a₁ + d(n - 1)
d represents the annual increase
Input the numbers
an = a₁ + d(n - 1)
289,400 = 206,300 + d(13 - 1)
289,400 = 206,300 + 12d
289,400 - 206,300 = 13d
83,100 = 12d
12d = 83,100
d = 83,100/12
d = 6,925
The annual increase is $6925
y-int: 140
slope: -4
to find the slope u gotta use the (y2-y1)/(x2-x1) formula
120-140 = -20
5-0 = 5
-20/5 = -4
Answer:
15a^5b^15
Step-by-step explanation:
you multiply 5 and 3 to get 15, and then when you are multiplying exponents of variables, you actually add them, so a^2 times a^3 is actually a^5, and b^7 times b^8 is b^15. Because these are all multiplied together, you get the answer of 15a^5b^15.
