What must you assume when you use a rate for a prediction? (Please Help!! I'm in 6th grade and this is math.)

Mathematics

1 answer:

murzikaleks [220]2 years ago

3 0

Answer:

For anything to do with force you have to assume an even amount of force is spread out evenly. But for things like growing rate you have all those variables so you can't assume a constant growing rate like acceleration.

Step-by-step explanation:

hope it helps (:

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maria purchased a new jacket for 78.12. the orginal price of the jacket was discounted 20% and Maria had to pay 5% sales tax. wh

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Sara plotted the locations of the trees in a park on a coordinate grid. She plotted an oak tree which was in the middle of the p

padilas [110]

Answer: $10.2\ yards$

Step-by-step explanation:

<h3> "Sara plotted the locations of the trees in a park on a coordinate grid. She plotted an oak tree, which was in the middle of the park, at the origin. She plotted a maple tree, which was 10 yards away from the oak tree, at the point (10,0) . Then she plotted a pine tree at the point (-2.4, 5) and an apple tree at the point (7.8, 5) What is the distance, in yards, between the pine tree and the apple tree in the</h3><h3>park?"</h3>

For this exercise you need to use the following formula, which can be used for calculate the distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

In this case, you need to find distance, in yards, between the pine tree and the apple tree in the park.

You know that pine tree is located at the point (-2.4, 5) and the apple tree is located at the point (7.8, 5).

So, you can say that:

$x_2=-2.4\\x_1=7.8\\\\y_2=5\\y_1=5$

Knowing these values, you can substitute them into the formula and then evaluate, in order to find the distance, in yards, between the pine tree and the apple tree in the park.

This is:

$d=\sqrt{(-2.4-7.8)^2+(5-5)^2}=10.2\ yards$