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GarryVolchara [31]
3 years ago
14

Jayden's new puppy weighed 11 1/4 pounds at 4 weeks old. At 16 weeks old, the puppy weighed 1 2/3 times more. How much did Jayde

n's puppy weigh at 16 weeks old?
Mathematics
1 answer:
Whitepunk [10]3 years ago
7 0
<h2><u>Answer:</u></h2><h2><u>18 3/4 pounds</u></h2>

<u></u>

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Anty was riding his bike to school at a speed of 12 mph. When he was of the way there, he got a flat tire. His mother drove him
NemiM [27]

Complete question:

Anty was riding his bike to school at a speed of 12 mph. When he was <u>half </u>of the way there, he got a flat tire. His mother drove him the rest of the way at a speed of 48 mph. What was his average speed?

Answer:

His average speed is 19.2 mph

Step-by-step explanation:

Given;

speed of Anty to school half of the way, v₁ = 12 mph

speed of Anty when his mother drove him half of the way, v₂ = 48 mph

The average speed of Anty is calculated as;

V_{average} = \frac{Total \ distance }{Total \ time }

The value of the average speed is closer to 12 mph than 48 mph because Anty spent more time moving at 12 mph than at 48 mph.

Let the equal distance travel at each speed = 96 miles

Time taken at 12 mph = \frac{96 \ mile}{12 \ m/h} = 8 \ hours

Time taken at 12 mph = \frac{96 \ mile}{48 \ m/h} = 2 \ hours

Average speed = \frac{Total \ distance}{Total \ time } = \frac{96 \ mile \ + \ 96 \ mile}{2\ hr \ + \ 8\ hr} = \frac{192 \ miles}{10 \ hrs} = 19.2 \ mph

Also, you can assume any other equal distance traveled at each speed, the average speed will still be 19.2 mph.

<u>Check:</u> let the equal distance traveled at each speed = 480 miles

Time taken at 12 mph = 480/12 = 40 hours

Time taken at 48 mph = 480/ 48 = 10 hours

Average speed = (480 + 480) / (40 + 10)

                          = 19.2 mph

8 0
3 years ago
How do you find the circumference and pie of a circle? Please help me I want to know. Please and thank you.
Paladinen [302]
Hope this helped C=2 PIE R

3 0
3 years ago
The fourth question
kodGreya [7K]

Step-by-step explanation:

Given:

AD is the bisector of ∠BAC

∠CPD = ∠BPD

1) ∠CAP = ∠BAP

Reason: definition of angle bisector

2) ∠CPD = 180 − ∠APC, ∠BPD = 180 − ∠APB

Reason: definition of supplementary angles

3) 180 − ∠APC = 180 − ∠APB

Reason: substitution

4) ∠APC = ∠APB

Reason: algebra

5) AP = AP

Reason: reflexive property

6) ΔAPC ≅ ΔAPB

Reason: ASA congruence

4 0
3 years ago
What is an explanation or picture of how to work out the problem 8.13-2.716
icang [17]

Answer:

5.414

subtract 8.13 from 2.716 and u will get ur answer

8 0
3 years ago
Factor completely, then place the answer in the proper location on the grid.
Tresset [83]
\mathrm{Factor\:out\:common\:term\:}9 \ \textgreater \  9\left(x^4-25y^8\right)

Factor \ \textgreater \  x^4-25y^8

\mathrm{Apply\:difference\:of\:squares\:rule:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)
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x^2-5y^4 \ \textgreater \  \mathrm{Apply\:difference\:of\:squares\:rule:\:}x^2-y^2=\left(x+y\right)\left(x-y\right)
x^2-5y^4=\left(x+\sqrt{5}y^2\right)\left(x-\sqrt{5}y^2\right)

\left(x^2+5y^4\right)\left(x+\sqrt{5}y^2\right)\left(x-\sqrt{5}y^2\right)

9\left(x^2+5y^4\right)\left(x+\sqrt{5}y^2\right)\left(x-\sqrt{5}y^2\right)

Hope this helps!
8 0
3 years ago
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