A complete load of concrete = 8 parts gravel + 7 parts water + 5 parts cement.
Total number of parts in every load = 8 + 7 + 5 = 20 parts
If total load = 220 kg, then 20 parts = 220 kg
Divide each side by 20 : 1 part = 11 kg
gravel = 8 parts = 8 x 11 kg = <em>88 kg</em>
water = 7 parts = 7 x 11 kg = <em>77 kg</em>
cement = 5 parts = 5 x 11 kg = <em>55 kg</em>
<u>Check:</u> 88 + 77 + 55 = 220 yay !
Okay its 1,6,7,12,14,19,22
1+5+1+5+2+5+3
27,31,36,41,46
<span>ABCD is an isosceles trapezoid with legs AB and CD
∴ AB = CD
</span>
<span>AB = 6y +5
</span>
<span>CD= 2y +1
∴ 6y + 5 = 2y + 1
6y - 2y = 5 - 1
4y = 4
∴ y = 4/4 = 1
</span>
I believe the answer is, not positive though
(-30m+33)
