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Vera_Pavlovna [14]

2 years ago

5

The equation x2 - 3x = 22

1 answer:

gizmo_the_mogwai [7]2 years ago

5 0

Answer:

x = - 3.42443 or 6.42443

Step-by-step explanation:

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Equivalent to 25+3(a−5)+7a.

Ilia_Sergeevich [38]

Answer:

25+3(a−5)+7a.

25+3a-15+7a

7a+3a+25-15

10a+10

10(a+1)

7 0

2 years ago

Marjani's garden contains roses, daffodils,and tulips.About 3/5 of the flowers are tulips.What percent of the flowers in Marjani

Alex Ar [27]

The fraction indicating the number of flowers that are not tulips is:
1- 3/5= 2/5

2/5
= 2/5* (100/100) (because 100/100= 1)
= 2/5* 100%
= 40%

The correct answer is A. 40 percent~

5 0

2 years ago

Question is in the picture. Please help!

Vsevolod [243]

Answer:

B is the correct answer

5 0

2 years ago

Consider the sphere. A sphere. A is the radius, d is the diameter, b is the great circle, and c is the center. Identify the part

V125BC [204]

Answers: D for it represents the diameter and A for represents the radius

4 0

2 years ago

Read 2 more answers

(-2/3)^7*(3/5)^6*(5/6)^5*(1/3)^-7 simplify of law of indices

Wewaii [24]

Answer:

$\boxed {-\frac{12}{5}}$

Step-by-step explanation:

Solve the following expression:

$(-\frac{2}{3})^{7} \times (\frac{3}{5})^{6} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

-Calculate $-\frac{2}{3}$ to the power of $7$ :

$(-\frac{2}{3})^{7} \times (\frac{3}{5})^{6} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

$-\frac{128}{2187} \times (\frac{3}{5})^{6} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

-Calculate $\frac{3}{5}$ to the power of $6$ :

$-\frac{128}{2187} \times (\frac{3}{5})^{6} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

$-\frac{128}{2187} \times (\frac{729}{15625}) \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

-Multiply both $-\frac{128}{2187}$ and $\frac{729}{15625}$ :

$-\frac{128}{2187} \times (\frac{729}{15625}) \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

$-\frac{128}{46875} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

-Calculate $\frac{5}{6}$ to the power of $5$ :

$-\frac{128}{46875} \times (\frac{5}{6})^{5} \times (\frac{1}{3})^{-7}$

$-\frac{128}{46875} \times (\frac{3125}{7776}) \times (\frac{1}{3})^{-7}$

-Multiply both $-\frac{128}{46875}$ and $\frac{3125}{7776}$ :

$-\frac{128}{46875} \times (\frac{3125}{7776}) \times (\frac{1}{3})^{-7}$

$-\frac{4}{3645} \times (\frac{1}{3})^{-7}$

-Calculate $\frac{1}{3}$ to the power of $-7$ :

$-\frac{4}{3645} \times (\frac{1}{3})^{-7}$

$-\frac{4}{3645} \times 2181$

-Multiply both the $-\frac{4}{3645}$ and $2187$ :

$-\frac{4}{3645} \times 2181$

$\boxed {-\frac{12}{5}}$

Therefore, the final answer is $-\frac{12}{5}$ .

3 0

2 years ago