I’m thinking it’s going to be 7 units. If it’s not right correct me
Using the hypergeometric distribution, it is found that there is a 0.0232 = 2.32% probability of getting exactly two winning numbers with one ticket.
<h3>What is the hypergeometric distribution formula?</h3>
The formula is:


The parameters are:
- x is the number of successes.
- N is the size of the population.
- n is the size of the sample.
- k is the total number of desired outcomes.
For this problem, the parameters are given as follows:
N =A + B = 54, k = 4, n = 4.
The probability of getting exactly two winning numbers with one ticket is P(X = 2), hence:


There is a 0.0232 = 2.32% probability of getting exactly two winning numbers with one ticket.
More can be learned about the hypergeometric distribution at brainly.com/question/24826394
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Answer:
3:8:5
Step-by-step explanation:
25:15:40
all can be divided by 5 but nothing else
therefore we get
5:3:8
in order of apple to coconut to orange juice it's
3:8:5
Answer:
10 is the answer. hj is 10
We have that
set of data [<span>8, 12, 15, 17, 18]
step 1
Find the mean
</span>[8+ 12 + 15 + 17 + 18]/5-------> 70/5------> 14
step 2
for each number: subtract the Mean and square the result
(8-14)²----->36
(12-14)²----> 4
(15-14)²----> 1
(17-14)²----> 9
(18-14)²----> 16
step 3
<span> work out the mean of those squared differences
[36+4+1+9+16]/5-----> 66/5-----> 13.2----> </span><span>this value is called the "Variance"
step 4
</span><span>Take the square root of that
</span>standard desviation=√13.2-----> 3.63-------> 4
the answer is
4