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3 years ago

Factor 6x4 – 5x2 + 12x2 – 10 by grouping. What is the resulting expression?

2 answers:

7 0

Your answer would be the last option, (6x² - 5)(x² + 2).
This is because when you expand it, you get:
6x² × x² = 6x⁴
6x² × 2 = 12x²
-5 × x² = -5x²
-5 × 2 = -10
Which are all the correct terms.

I hope this helps!

aev [14]3 years ago

7 0

1. Factor out common terms in the first two terms, then in the last two terms
x^2(6x^2-5)+2(6x^2-5)

2. Facto out the common term 6x^2-5
(6x^2-5)(x^2+2)

Have a nice day :D

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RESPONDE LAS PREGUNTAS 8, 9 Y 10 DE ACUERDO CON LA

andrew-mc [135]

Answer:

ANSWER QUESTIONS 8, 9 AND 10 ACCORDING TO THE

NEXT INFORMATION

Luis painted a mural that

has 760 cm of

perimeter; your measurements are

show in the following

figure.

8. The expression associated with the length of the mural: 2x - 40, is

can interpret as

A. the length is 40 cm less than twice its width

B. the length exceeds the width value by 40 cm

C. the width squared, minus 40 cm, equals the length

D. 40 cm minus twice the width is the value of the length

9. What are the measurements in centimeters of the mural?

A. length: 150, width: 190 B. length: 210, width: 250

B. length: 210, width: 250

C. length: 240, width: 140 D. length: 230, width: 190

D. length: 230, width: 190

10. The area Luis used to paint the mural is

A. 2 [(2x - 40) + x] B. 2x2 - 40x

B. 2x2 - 40x

C. (2x) x - 40 D. x2 - 40x

D. x2 - 40x

Step-by-step explanation:

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3 years ago

Reuben has scores of 70,75,83, and 80 on four spanish quizzes. what score must he get on the next quiz to achieve an average of

Sergio [31]

X - the score he must get

$\frac{70+75+83+80+x}{5} \geq 80 \\
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3 years ago

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Use undetermined coefficient to determine the solution of:y"-3y'+2y=2x+ex+2xex+4e3x

Kitty [74]

First check the characteristic solution: the characteristic equation for this DE is

r ² - 3r + 2 = (r - 2) (r - 1) = 0

with roots r = 2 and r = 1, so the characteristic solution is

y (char.) = C₁ exp(2x) + C₂ exp(x)

For the ansatz particular solution, we might first try

y (part.) = (ax + b) + (cx + d) exp(x) + e exp(3x)

where ax + b corresponds to the 2x term on the right side, (cx + d) exp(x) corresponds to (1 + 2x) exp(x), and e exp(3x) corresponds to 4 exp(3x).

However, exp(x) is already accounted for in the characteristic solution, we multiply the second group by x :

y (part.) = (ax + b) + (cx ² + dx) exp(x) + e exp(3x)

Now take the derivatives of y (part.), substitute them into the DE, and solve for the coefficients.

y' (part.) = a + (2cx + d) exp(x) + (cx ² + dx) exp(x) + 3e exp(3x)

… = a + (cx ² + (2c + d)x + d) exp(x) + 3e exp(3x)

y'' (part.) = (2cx + 2c + d) exp(x) + (cx ² + (2c + d)x + d) exp(x) + 9e exp(3x)

… = (cx ² + (4c + d)x + 2c + 2d) exp(x) + 9e exp(3x)

Substituting every relevant expression and simplifying reduces the equation to

(cx ² + (4c + d)x + 2c + 2d) exp(x) + 9e exp(3x)

… - 3 [a + (cx ² + (2c + d)x + d) exp(x) + 3e exp(3x)]

… +2 [(ax + b) + (cx ² + dx) exp(x) + e exp(3x)]

= 2x + (1 + 2x) exp(x) + 4 exp(3x)

… … …

2ax - 3a + 2b + (-2cx + 2c - d) exp(x) + 2e exp(3x)

= 2x + (1 + 2x) exp(x) + 4 exp(3x)

Then, equating coefficients of corresponding terms on both sides, we have the system of equations,

x : 2a = 2

1 : -3a + 2b = 0

exp(x) : 2c - d = 1

x exp(x) : -2c = 2

exp(3x) : 2e = 4

Solving the system gives

a = 1, b = 3/2, c = -1, d = -3, e = 2

Then the general solution to the DE is

y(x) = C₁ exp(2x) + C₂ exp(x) + x + 3/2 - (x ² + 3x) exp(x) + 2 exp(3x)

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3 years ago

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denis-greek [22]

Answer:

We need to find the first term. We can use the formula

an = a1 + d(n - 1)

to solve for a1. We already know the 12th term, a12, common difference, d, and nth sequence, n.

a12 = -36

d = -4

n = 12

-36 = a1 - 4(12 - 1)

-36 = a1 - 44

8 = a1

The first term is 8. Therefore, your formula is

an = 8 - 4(n - 1)

an = -4n + 12

Then use this formula to graph.

n is the independent variable.

an is the dependent variable.

Your graph will be a line.

n | an

___________

1 8

2 4

3 0

4 -4

5 -8

6 -12

Step-by-step explanation:

give me brainliest.

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3 years ago