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sukhopar [10]
3 years ago
10

One would not expect yeast to undergo fermentation in the presence of

Chemistry
1 answer:
Hunter-Best [27]3 years ago
3 0

Answer:

Oxygen.

Explanation:

Hello,

Yeast fermentation in the food industry must be carried out under anaerobic conditions as long as when oxygen is present respiration occurs rather than fermentation.

Best regards.

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I NEED HELP PLEASE, THANKS! :)
vaieri [72.5K]

Answer:

This process is known as doping. It can be done by adding either of two types of impurity to the crystal.

(A) By adding electron rich impurities i.e., group 15 elements to the silicon and germanium of group 14 elements.

hope it's helpful

8 0
3 years ago
Iupac name of h3C-C-Ch2-ch3​
pshichka [43]

Answer:

The IUPAC name of given compound is 3−5−ethyl−5−−3−methylheptane. Explanation: The parental chain is of 7 carbons with single bonds hence it is heptane. Two substituents ethyl and methyl group are attached from an equal distance. Hence according to the alphabetical order preference, counting starts from carbon which is close to an ethyl group.

8 0
2 years ago
Given the formula: what is a chemical name of this compound? propane propanal propanol propanone
katrin [286]
1) Chemical formula for propane is CH₃-CH₂-CH₃. 
Propane is a three carbon alkane (acyclic saturated <span>hydrocarbon).
</span>2) Chemical formula for propanal is CH₃-CH₂-CH=O.
Propanal <span> is a </span>saturated<span> three carbon </span>aldehyde (have<span> a </span>carbonyl<span> center).
3) </span>Chemical formula for propanol is CH₃-CH₂-CH₂-OH.
1-propanol <span> is a </span><span>primary alcohol.
4) </span>Chemical formula for propanone is (CH₃)₂-C=O.
Propanone or acetone is <span>he simplest and smallest</span> ketone.
7 0
3 years ago
Calculate the percentage by mass of chlorine in Cobalt (II) chloride (cocl2)​
Likurg_2 [28]

Explanation:

Divide the mass of chlorine by the molar mass of cobalt chloride, then multiply by 100.

Molar Mass of Cobalt Chloride.

Mass of Chlorine in Cobalt Chloride.

Percent Composition of Chlorine.

8 0
3 years ago
Read 2 more answers
1) A light bulb takes in 30 of energy per second. It transfers 3j as use
natta225 [31]

Answer:

\boxed{\text{10 \%}}

Explanation:

The formula for efficiency is  

\begin{array}{rcl}\text{Efficiency} & = & \dfrac{\text{useful energy out}}{\text{energy in}} \times 100 \,\% \\\\\eta & = & \dfrac{w_{\text{out}}}{w_{\text{in}} } \times 100 \,\%\\\end{array}

Data:

Useful energy =  3 J

Energy input  = 30 J

Calculation:

\begin{array}{rcl}\eta & = & \dfrac{\text{3 J}}{\text{30 J}} \times 100 \,\%\\\\\eta & = & 10 \, \%\\\end{array}\\\text{ The efficiency is }\boxed{\textbf{10 \%}}

8 0
3 years ago
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