A fragment of who’s prudent and not the only one who is the a front
Answer:
219.95 °C
Explanation:
Given data:
Volume of gas = 9.71 L
Initial pressure = 209 torr (209/760 = 0.275 atm)
Initial temperature = 10.1 °C (10.1 +273 = 283.1 K)
Final temperature = ?
Final pressure = 364 torr (364/760 =0.479 atm)
Solution:
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
0.275 atm / 283.1 K = 0.479 atm/T₂
T₂ = 0.479 atm × 283.1 K/ 0.275 atm
T₂ = 135.6 atm. K /0.275 atm
T₂ = 493.1 K
Kelvin to °C:
493.1 K - 273.15 = 219.95 °C
1) State the chemical reaction
4M + O2 ---> 2M2O
2) State the molar ratios
4 mol M : 1 mol O2 : 2 mol M2O
3) Calculate the number of moles of M2O produced
4 mol M / 2 mol M2O = 2 mol M / x => x = 2 mol M * 2 mol M2O / 4 mol M
=> x = 1 mol M2O
4) Calculate the molar mass of M2O
molar mass = mass in grams / number of moles = 62.0 g / 1 mol = 62.0 g/mol
5) Calculate the atomic mass of M
molar mass of M2O = 2 * atomic mass of M + atomic mass of O =>
62.0 = 2 * atomic mass of M + 16
=> atomic mass of M = [62.0 - 16] / 2 = 23
6) Compare that atomic mass with the atomic masses of the metals in the periodic table.
You will find that 23 is the atomic mass of sodium.
Answer: sodium
Answer:
2.29 moles of SF₆ contain 334.5 g SF₆
Explanation:
Given data:
Mass of SF₆ = ?
Number of moles of SF₆ = 2.29 mol
Solution:
Formula:
Mass = number of moles × molar mass
Molar mass of SF₆ = 32.065 + (19)×6
Molar mass of SF₆ = 146.06 g/mol
Now we will put the values in formula.
Mass = 2.29 mol × 146.06 g/mol
Mass = 334.5 g
2.29 moles of SF₆ contain 334.5 g SF₆ .