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Aneli [31]
3 years ago
5

How many ridges would there be on $10 worth of quarters?

Mathematics
2 answers:
Virty [35]3 years ago
5 0

Answer:

4,760 ridges

Step-by-step explanation:

10(119x4)

(pemdas)

119x4=476x10=4760

tresset_1 [31]3 years ago
4 0

Answer:

4760

Step-by-step explanation:

First you find out how many are in a dollar so you do

119*4 which is 476

Then because there is $10 you need to do

476 * 10 which would be 4760

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Verify identity list steps. Cot(t)(1-cos^2(t))=cos(t)sin(t)
storchak [24]
Remember: We have to work from either the LHS or the RHS.
(Left hand side or the Right hand side)

You should already know this:

\huge{Cot(t) = \frac{1}{tan(t)} = \frac{1}{\frac{sin(t)}{cos(t)}} = 1\div \frac{sin(t)}{cos(t)} = 1\times \frac{cos(t)}{sin(t)}=\boxed{\frac{cos(t)}{sin(t)}}


You should also know this:

sin^2(t) + cos^2(t) = 1\\\\\boxed{sin^2(t)} = 1 - cos^2(t)

So plugging in both of those into our identity, we get:

\frac{cos(t)}{sin(t)}\cdot sin^2(t) = cos(t)\cdot sin(t)

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4 0
3 years ago
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kompoz [17]

Answer:

The answer is 1030 ml

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5 0
3 years ago
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The length of a rectangle is 5 more than twice the width. the perimeter is 130 inches. what is te area
Brut [27]
The length of a rectangle:
L =  2 W  + 5
The perimeter:
P = 2 L + 2 W
130 = 2 · ( 2 W + 5 ) + 2 W
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120 = 6 W
W = 120 : 6
W = 20 in
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Finally the area:
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Answer:

B

Step-by-step explanation:

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3 years ago
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