How many ridges would there be on $10 worth of quarters?
2 answers:
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The missing figure is attached
The value of a is ⇒ 2nd answer
Step-by-step explanation:
Let as revise the Pythagoras Theorem
In the right triangle ABC, where ∠B is a right angle (AC is the hypotenuse, Ab and BC are the legs of the right angle)
- (AC)² = (AB)² + (BC)²
- (AB)² = (AC)² - (BC)²
- (BC)² = (AC)² - (AB)²
If BD is drawn perpendicular to AC, we can use these rules
- (AB)² = AD × AC
- (BC)² = CD × AC
- (BD)² = AD × CD
- AB × BC = BD × AC
In Δ WYZ
∵ m∠WYZ = 90°
- By using Pythagoras Theorem
∴ (WZ)² = (WY)² + (YZ)²
∵ WY = 4 units
∵ YZ = 3 units
∵ WZ = c units
∴ c² = (4)² + (3)²
∴ c² = 16 + 9 = 25
- Take √ for both sides
∴ c = 5
In Δ XWZ
∵ m∠XWZ = 90°
∵ WY ⊥ XZ
- We can use the rule (WZ)² = ZY × ZX
∵ (WZ)² = ZY × ZX
∵ WZ = 5 units
∵ ZY = 3 units
∵ ZX = (3 + a) units
∴ (5)² = 3(3 + a)
∴ 25 = 9 + 3a
- Subtract 9 from both sides
∴ 16 = 3a
- Divide both sides by 3
∴ a =
The value of a is
Learn more:
You can learn more about the rules of the right triangle in brainly.com/question/14390928
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