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marshall27 [118]
3 years ago
9

How to combine like terms

Mathematics
1 answer:
aev [14]3 years ago
8 0

Example: 1x+2y+3z+4a+5x+6y+7z+8+9

We can see that there is more than one number with the variable x, therefore, we say they're ''like terms'' and because of that they can be summed. We do this with all of the other numbers with similar variables. If no numbers with similar variables are left, like 4a, you don't do anything but write them as they are. You can also see that 8 and 9 can also be summed because neither of them has a variable, therefore they're similar.

In this step, you just do the operation with the numbers and keep the same variable.

(1x+5x)+(2y+6y)+(3z+7z)+4a+(8+9)

(6x)+(8y)+(10z)+4a+(17)

since there are not more numbers similar in variables, this operation is done.

6x+8y+10z+4a+17

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8 1/8 divided by 2 1/2
Alexxandr [17]

\huge\mathcal\pink{Answer}

3 1/4 is the right answer

5 0
3 years ago
What is the slope of the line that passes through the points (-3, 5) and (1, 7)?
Stells [14]

Answer: The slope of the line is \frac{1}{2}

Step-by-step explanation:

The slope of a line can be calculated with the following formula:

m=\frac{y_2-y_1}{x_2-x_1}

Then, given the points (-3, 5) and (1, 7), you can identify that:

y_2=5\\y_1=7\\\\x_2=-3\\x_1=1

Knowing these values you can substitute them into the formula for calculate the slope:

m=\frac{5-7}{-3-1}

Finally, evaluating, you get that the slope of that line is:

m=\frac{-2}{-4}\\\\m=\frac{1}{2}

8 0
3 years ago
Expand (- 3a - 5x) (- 2b - 4y).​
vekshin1

Answer:  −3a(−2b−4y).−5x(−2b−4y). to this  

6ab+12ay+10bx+20xy

Step-by-step explanation: hope this helps :)

8 0
3 years ago
Read 2 more answers
Second Time Asking This:
sattari [20]

128 ÷3=42.66

it doesn't say if they have to pay the money back but if they do it's

128-35= 43

43÷3= 14.33

8 0
3 years ago
Solve for the indicated variable: ⅖(z + 1) = y for z.
sweet [91]

Answer:

  z = 5/2y -1

Step-by-step explanation:

We observe that z has ...

  • 1 added
  • the sum multiplied by 2/5

To solve for z, we undo these operations in reverse order.

  \dfrac{2}{5}(z+1)=y\qquad\text{given}\\\\z+1=\dfrac{5}{2}y\qquad\text{multiply by 5/2}\\\\\boxed{z=\dfrac{5}{2}y-1}\qquad\text{subtract 1}

5 0
3 years ago
Read 2 more answers
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