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Mathematics

2 answers:

Sav [38]3 years ago

4 0

I think the answer is B: Graphing rise in sea level with time

VARVARA [1.3K]3 years ago

3 0

I belive its D dont take my word for it but i belive that is the answer

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Will mark brainlist and rate 5/5

erastova [34]

Sir you don’t even have a question

5 0

3 years ago

here’s a graph of the equation x + 3y = 6 select all coordinates pairs that represent a solution to the equation A) 0,2 B) 0,6 C

Afina-wow [57]

Answer:

(0,2) (3,1)

Step-by-step explanation:

5 0

3 years ago

Is x+y+1=0 a tangent of both y^2=4x and x^2=4y parabolas?

Lubov Fominskaja [6]

Answer:

yes

Step-by-step explanation:

The line intersects each parabola in one point, so is tangent to both.

For the first parabola, the point of intersection is ...

y^2 = 4(-y-1)

y^2 +4y +4 = 0

(y+2)^2 = 0

y = -2 . . . . . . . . one solution only

x = -(-2)-1 = 1

The point of intersection is (1, -2).

For the second parabola, the equation is the same, but with x and y interchanged:

x^2 = 4(-x-1)

(x +2)^2 = 0

x = -2, y = 1 . . . . . one point of intersection only

___

If the line is not parallel to the axis of symmetry, it is tangent if there is only one point of intersection. Here the line x+y+1=0 is tangent to both y^2=4x and x^2=4y.

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Another way to consider this is to look at the two parabolas as mirror images of each other across the line y=x. The given line is perpendicular to that line of reflection, so if it is tangent to one parabola, it is tangent to both.