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3 years ago

6

here’s a graph of the equation x + 3y = 6 select all coordinates pairs that represent a solution to the equation A) 0,2 B) 0,6 C

) 2,6 D) 3,1 E) 4,1 F 6,2

1 answer:

Afina-wow [57]3 years ago

5 0

Answer:

(0,2) (3,1)

Step-by-step explanation:

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No

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x + 1 is not a factor of the polynomial because the remainder is 2 and not 0

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ms green tell you that a right triangle has a hypotenuse of 13 and a leg of 5 . She asks you to find the other leg of the triang

Montano1993 [528]

Answer:

$\large \boxed{12}$

Step-by-step explanation:

We can apply Pythagoras' Theorem.

$\begin{array}{rcc}a^{2} & = & b^{2} + c^{2}\\13^{2}& = & 5^{2} + c^{2}\\169& = & 25 + c^{2}\\c^{2}& = & 144\\c & = & \sqrt{144}\\& = & \mathbf{12}\\\end{array}\\\text{The other leg of the triangle is $\large \boxed{\mathbf{12}}$}$

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3 years ago

What are the coordinates of point B on \overline{AC} such that AB = 1/2 BC

marta [7]

Answer:

C. $B(x,y) = \left(3,-\frac{16}{3} \right)$

Step-by-step explanation:

Let $A(x,y) = (6,-7)$ , $B(x,y) = (x,y)$ and $C(x,y) = (-3,-2)$ . From statement we know that $AB = \frac{1}{2}\cdot BC$ , which is equivalent to the following linear algebraic formula:

$B(x,y) -A(x,y) = \frac{1}{2}\cdot [C(x,y)-B(x,y)]$ (1)

$B(x,y)-A(x,y) = \frac{1}{2}\cdot C(x,y)-\frac{1}{2}\cdot B(x,y)$

$\frac{3}{2}\cdot B(x,y) = \frac{1}{2}\cdot C(x,y)+A(x,y)$

$B(x,y) = \frac{1}{3}\cdot C(x,y) +\frac{2}{3}\cdot A(x,y)$ (2)

Then, the coordinates of point B on AC are:

$B(x,y) = \frac{1}{3}\cdot (-3,-2)+\frac{2}{3}\cdot (6,-7)$

$B(x,y) = \left(-1, -\frac{2}{3}\right)+\left(4, -\frac{14}{3} \right)$

$B(x,y) = \left(3,-\frac{16}{3} \right)$

Which means that correct answer is C.

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Step-by-step explanation:

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