Answer:
probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3
Step-by-step explanation:
First of all;
Let B1 be the event that the card with two red sides is selected
Let B2 be the event that the
card with two black sides is selected
Let B3 be the event that the card with one red side and one black side is
selected
Let A be the event that the upper side of the selected card (when put down on the ground)
is red.
Now, from the question;
P(B3) = ⅓
P(A|B3) = ½
P(B1) = ⅓
P(A|B1) = 1
P(B2) = ⅓
P(A|B2)) = 0
(P(B3) = ⅓
P(A|B3) = ½
Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;
P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]
Thus;
P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]
P(B3|A) = (1/6)/(⅓ + 0 + 1/6)
P(B3|A) = (1/6)/(1/2)
P(B3|A) = 1/3
(a). To calculate Y at equilibrium
Y = C + I + G
Y = 40 + 0.8(Y – 0 + 10 + 20)
Y = 350
(b). To calculate C, I and G at Equilibrium
C = 40 + 0.8 Y
Since Y = 350
C = 40 + 0.8(350)
C = 40 + 280
C = 320
I = 20
G = 10
(c).To find
equilibrium Y
Given,
EX = 4 + 3EP/P
IM = 8 + 0.1 (Y - T) - 2EP/P
E = 3
P = 1
P = 1.5
Y = 170
Answer:
14-3n
Step-by-step explanation:
Answer;
D. The sidelines are parallel because they are perpendicular to the same line
Explanation;
According to the perpendicular Transversal Theorem , In a plane, if a line is perpendicular to one of two parallel lines , then it is perpendicular to the other line also. Additionally, the converse perpendicular transversal theorem states that, in a plane, if two lines are perpendicular to the same line, then they are parallel. Thus, the sidelines are parallel and also perpendicular to the same line.
