Answer:
6 Days
Step-by-step explanation:
Practically:
It takes,
10 Men ( complete ) 5 Copies --> 6 Days
So, 2 Men can complete 1 copy in 6 days.
Question asks us :
8 Men ( complete ) 4 Copies --> X Days
It will take 6 days because the proportion of men to copies is same as the first equation.
Theoretically:
10 Men 5 Copies 6 Days
8 Men 4 Copies X Days
> 6/X = 8/10 ( If men decrease the number of days increase. So, it is an indirect proportion. ) . 5/4 ( If copies decrease the number of days decrease as well. So, it is a direct proportion. )
> 6/X = 8/10 . 5/4
> 6/X = 40/40
> 6/X = 1
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> X=6</h2><h2>
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I hope it will be understood.</em></h2><h2><em>
If I have any inaccuracies please let me know.</em></h2><h2><em>
Have a nice day and never stop questioning!</em></h2><h3><em>
</em></h3>
Can someone answer on my profile just the 2 and I’ll give brainlist
There are 26 letters. There are 10 digits. Different combos possible are 26 * 26 * 10 * 10
Basically 67,600 different passwords can be formed. Rate and Thank if helped! :)
Answer:
its 1,3,4,and 7
Step-by-step explanation:
i just did it
so A,C,D,and G
Answer:
Approximately 
(
.) (Assume that the choices of the 
passengers are independent. Also assume that the probability that a passenger chooses a particular floor is the same for all 
floors.)
Step-by-step explanation:
If there is no requirement that no two passengers exit at the same floor, each of these passenger could choose from any one of the floors. There would be a total of 
unique ways for these 
passengers to exit the elevator.
Assume that no two passengers are allowed to exit at the same floor.
The first passenger could choose from any of the floors.
However, the second passenger would not be able to choose the same floor as the first passenger. Thus, the second passenger would have to choose from only 
floors.
Likewise, the third passenger would have to choose from only 
floors.
Thus, under the requirement that no two passenger could exit at the same floor, there would be only 
unique ways for these two passengers to exit the elevator.
By the assumption that the choices of the passengers are independent and uniform across the floors. Each of these 
combinations would be equally likely.
Thus, the probability that the chosen combination satisfies the requirements (no two passengers exit at the same floor) would be:
.
