Answer:
21 ft by 66 ft
Step-by-step explanation:
From the question,
P = 2(L+W)............... Equation 1
Where P = Perimeter of the playing Field, L = Length of the playing Field, W = width of the playing Field.
If the Length of the Field is 45 ft longer than the width,
L = 45+W............ Equation 2
Substitute Equation 2 into equation 1
P = 2(45+W+W)
P = 90+4W............. Equation 3
Given: P = 174 ft.
Substitute into equation 3
174 = 90+4W
4W = 174-90
4W = 84
W = 84/4
W = 21 ft.
Substituting the value of W into equation 2
L = 45+21
L = 66 ft.
Hence the dimensions of the playing field is 21 ft by 66 ft
The pudu weighed approximately 1 pound at birth.
Given that the New York Queens Zoo celebrated the birth of a Southern pudu deer in July of 2013 which tipped the scale of a mere 0.45 kg, to determine, given that one kilogram is approximately equal to 2.2 pounds, about how many pounds did the pudu weigh at birth, the following calculation must be performed:
- 1 = 2.2
- 0.45 = X
- 0.45 x 2.2 = X
- 0.99 = X
Therefore, the pudu weighed approximately 1 pound at birth.
Learn more about maths in brainly.com/question/18673356
Answer:
<h2>4 terms</h2>
Step-by-step explanation:
Term 1: 5x^3
Term 2: 8x^2y
Term 3: 4xy
Term 4: 4
Answer:
11. x=18, y=5
12. x=17, y=9
Step-by-step explanation:
Use the angle property https://www.proprofs.com/quiz-school/story.php?title=angle-properties-parallel-lines (REFER TO THIS LINK)
Answer:
a = 
x = 
Step-by-step explanation:
Let's solve for a.
8x−5x+4−x=ax+8
Step 1: Flip the equation.
ax+8=2x+4
Step 2: Add -8 to both sides.
ax+8+−8=2x+4+−8
ax=2x−4
Step 3: Divide both sides by x.
Let's solve for x.
8x−5x+4−x=ax+8
Step 1: Add -ax to both sides.
2x+4+−ax=ax+8+−ax
−ax+2x+4=8
Step 2: Add -4 to both sides.
−ax+2x+4+−4=8+−4
−ax+2x=4
Step 3: Factor out variable x.
x(−a+2)=4
Step 4: Divide both sides by -a+2.
Hope this helps!
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