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Anika [276]
3 years ago
14

Your jewelry business orders $1320 in supplies each month. In each month, you can usually sell an earring/ring set for about $55

each. How many sets do you need to sell each month to break even?
If you found that your total profit for a month was $715, how many sets did you sell?

If you had a month where 7 sets were sold, how much profit did you make?
Mathematics
1 answer:
steposvetlana [31]3 years ago
8 0

Answer:

Given,

The jewelry business orders $ 1320 in supplies each month.

That is, the invested amount = $ 1320,

Also, the selling price of each earring/ring set = $ 55,

Part 1 : Let x be the number of set that have been sold each month to break even ( in which revenue and invested amount are equal )

So, Total revenue ( the cost of x sets) = 55x,

⇒ 55x = 1320

Divide both sides by 55,

We get,

x = 24

Hence, 24 sets are needed to sell each month to break even.

Part 2 : Let y be the number of sets in which the profit is $ 715,

Total revenue = 55x

Profit = Total revenue - invested amount

⇒ 55x - 1320 = 715,

⇒ 55x = 715 + 1320

⇒ 55x = 2035

⇒ x = 37

Hence, 37 sets are sold for the total profit of $715.

Part 3 :

Revenue in selling 7 sets = 55 × 7 = $ 385

Profit = $ 385 - $ 1320 = - $ 935

Hence, the profit is - $ 935 after selling 7 sets.

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Answer:

To write repeated multiplication of the same number in exponential notation, first write the number being multiplied as the base. Then count how many times that number is used in the multiplication, and write that number as the exponent.

Step-by-step explanation:

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2 years ago
Pentagon RSTUV is circumscribed about a circle. What is the value of x if RS = 10, ST = 13, TU = 11, UV = 12, and VR = 12?
Kobotan [32]

Answer:

Step-by-step explanation:

The value of x is 7 ⇒ 1st answer

Step-by-step explanation:

* Lets revise a fact in the circle

- The two tangents drawn from a point out side the circle are equal

∵ RSTUV is circumscribed about a circle

∴ Each side of the pentagon is a tangent to the circle

- Look to the attached figure to know how we will solve the problem

- Each tangent divided into two parts

# RS = x + y

∵ RS = 8

∴ x + y = 8 ⇒ (1)

# RV = x + n

∵ RV = 12

∴ x + n = 12 ⇒ (2)

- Subtract (2) from (1)

∴ y - n = -4 ⇒ (3)

# ST = y + z

∵ ST = 12

∴ y + z = 12 ⇒ (4)

# TU = z + m

∵ TU = 15

∴ z + m = 15 ⇒ (5)

- Subtract (5) from (4)

∴ y - m = -3 ⇒ (6)

# UV = m + n

∵ UV = 9

∴ m + n = 9 ⇒ (7)

- Add (6) and (7)

∴ y + n = 6 ⇒ (8)

- Lets solve equation (3) and equation (8) to find y

∵ y - n = -4 ⇒ (3)

∵ y + n = 6 ⇒ (8)

- Add (3) and (8)

∴ 2y = 2 ⇒ divide two sises by 2

∴ y = 1

- Lets substitute the value of y in equation (1)

∵ x + y = 8 ⇒ (1)

∵ y = 1

∴ x + 1 = 8 ⇒ subtract (1) from both sides

∴ x = 7

* The value of x is 7

plz mark me as brainlyist thxx

7 0
3 years ago
Read 2 more answers
Suppose that you work for the child social services agency in your county. Your job is to investigate instances of possible chil
True [87]

Answer:

Null hypothesis: ∪ =  No possible child abuse or neglect

Alternative hypothesis: Uₐ = Possible child abuse or neglect

Step-by-step explanation:

Null hypothesis: ∪ =  No possible child abuse or neglect

Alternative hypothesis: Uₐ = Possible child abuse or neglect

A type I error occurs when you reject the null hypothesis when it is true. In this situation, a type I error occurs when you conclude on possible child neglect or abuse and place the child in protective custody

A type II error occurs when you accept the null hypothesis when it is false. In this instance, a type II error occurs when you conclude on no possible child abuse or neglect when there is and fail to remove the child from the home.

In this case, the type II error is the more serious error. Failure to remove the child when there is possible child abuse or neglect will lead to more detrimental effect. Although, the type I error is also serious, it is not so detrimental as the type II error.

5 0
3 years ago
A converging lens of focal length 5 cm is placed at a distance of 20
lesya [120]

The object should be placed 20/cm from the lens so as to form its real image on the screen

<h3>Mirror equation</h3>

The mirror equation is given according to the expression below;

1/f = 1/u + 1/v

where

f is the focal length

u is the object distance

v is the image distance

Given the following parameters

f = 5cm

v = 20cm

Required

object distance u

Substitute

1/5 = 1/u +1/20

1/u = 1/5-1/20
1/u = 3/20

u = 20/3 cm

Hence the object should be placed 20/cm from the lens so as to form its real image on the screen

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4 0
2 years ago
Charli bought 2 3/4 pounds of pears for 0.76 per pound and 2 3/4 pounds of grapes for 1.40 per pound. how much money in dollars
MArishka [77]

Answer:

Total = \$5.94 ---- in dollars

Total = 594\ cents ---- in cents

5 dollars 94 cents

Step-by-step explanation:

Given

Pears

Weight = 2\frac{3}{4}\ lb

Amount = \$0.76 per pound

Grapes

Weight = 2\frac{3}{4}\ lb

Amount = \$1.40 per pound

Required

Determine the amount paid for the fruit in dollar and cents

First, we need to calculate the amount paid for each fruit.

This is calculated by multiplying the amount per pound by the number of pounds bought.

For Pears:

Total_{Pears} = 2\frac{3}{4} * \$0.76

Convert fraction to decimal

Total_{Pears} = 2.75 * \$0.76

Total_{Pears} = \$2.09

For Grapes

Total_{Grapes} = 2\frac{3}{4} * \$1.40

Convert fraction to decimal

Total_{Grapes} = 2.75 * \$1.40

Total_{Grapes} = \$3.85

Next, we add both amounts together to get the total amount spent in dollars.

Total = Total_{Pears} + Total_{Grapes}

Total = \$2.09 + \$3.85

Total = \$5.94

Multiply by 100 to convert this amount to cents

Total = 5.94 * 100\ cents

Total = 594\ cents

And it can be represented as dollars and cents as:

5 dollars 94 cents

8 0
3 years ago
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