Question

If , x - 12 square root of x + 36 = 0what is the value of x? A. 6 B. 6^2 C. 6^3 D. 6^4

Answer 1

Answer:

Option B) $6^2$ is correct.

That is in the given equation $x-12\sqrt{x}+36=0$ the value of x is  $6^2$

ie., $x=6^2$

Step-by-step explanation:

The given equation is $x-12\sqrt{x}+36=0$

To find the value of x in the given equation :

$x-12\sqrt{x}+36=0$

Rewritting the above equation as below :

$\sqrt{x}^2-2(\sqrt{x})(6)+6^2=0$

Which is in the form of $(a-b)^2=a^2-2ab+b^2$

Here $a=\sqrt{x}$ and b=6

Therefore it can be written as

$(\sqrt{x}-6)^2=0$

$\sqrt{x}-6=0$

$\sqrt{x}=6$

Squaring on both sides we get

$(\sqrt{x})^2=6^2$

$x=6^2$

Therefore in the given equation $x-12\sqrt{x}+36=0$ the value of x is $6^2$

Therefore Option B) $6^2$ is correct.