1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Archy [21]
3 years ago
5

You hold a bucket in one hand. In the bucket is a 500 g rock. You swing the bucket so the rock moves in a vertical circle 2.2 m

in diameter. What is the minimum speed the rock must have at the top of the circle if it to always stay-in contact with the bottom of the bucket?
Physics
1 answer:
slavikrds [6]3 years ago
6 0

Answer:v=3.28 m/s

Explanation:

Given

mass of rock m=500 gm

diameter of circle d=2.2 m

radius r=\frac{2.2}{2}=1.1 m

At highest Point

mg+N=\frac{mv^2}{r}

At highest Point N=0 because mass is just balanced by centripetal Force

thus mg=\frac{mv^2}{r}

v=\sqrt{gr}

v=\sqrt{9.8\times 1.1}

v=\sqrt{10.78}

v=3.28 m/s

You might be interested in
What does an Astronomer study? *
ratelena [41]

Answer:

an astronomer studies planets, stars, moons, etc, or objects that are outside the field of Earth.

3 0
3 years ago
Question 1 (1 point)
Sonbull [250]

Answer:

Solid objects will deform when adequate loads are applied to them; if the material is elastic, the object will return to its initial shape and size after removal. This is in contrast to plasticity, in which the object fails to do so and instead remains in its deformed state.

Explanation:

4 0
2 years ago
Read 2 more answers
What force caused the movements of the continents from one supercontinent to their present positions
AVprozaik [17]
The convection currents in the mantle caused the crust on top to break apart & go different directions.
6 0
3 years ago
A golf ball comes to rest 1.90 seconds after hitting a net. The force of the net slowed the ball down at a rate of 56.3 m/s^2. W
Nadusha1986 [10]

Answer:

The velocity of the ball when it first hit the net is Vi= 106.97 m/s

Explanation:

Vf= 0

Vi= ?

a= 56.3 m/s²

t= 1.9 s

Vf= Vi - a*t

Vi= a*t

Vi= 106.97 m/s

8 0
3 years ago
A point charge q1 = -4.00 nC is at the point x = 0.60 m, y = 0.80 m , and a second point charge q2 = +6.00 nC is at the point x
makkiz [27]

Answer:

A)Magnitude of the net electric field at the origin due q₁ and q₂

E₀= 131.6 N/C

B) Direction of the net electric field at the origin due q₁ and q₂

β=3.91°

Explanation:

Conceptual analysis

The electric field at a point P due to a point charge is calculated as follows:

E = k*q/d²

E: Electric field in N/C

q: charge in Newtons (N)

k: electric constant in N*m²/C²

d: distance from charge q to point P in meters (m)

The electric field at a point P due to several point charges is the vector sum of the electric field due to individual charges.

Equivalences

1nC= 10⁻⁹ C

Data

q₁ = -4 nC = -4*10⁻⁹ C

q₂ = +6nC =+ 6*10⁻⁹ C

k = 9*10⁹ N*m²/C²

d_{1} =\sqrt{0.6^{2}+0.8^{2}  } =1 m

d₂ = 0.6 m

Graphic attached

The attached graph shows the field in x=0, y=0, due to the charges q₁ and q₂:

E₁: Total field at point x=0 , y=0 due to charge q₁. As the charge q₁ is negative (q₁-), the field enters the charge.

E₂: Total field at point  x=0 , y=0  due to charge q₂. As the charge q2 is positive (q₂+) ,the field leaves the charge.

Calculation of the electric field at the origin of x-y coordinates due to the charge q₁

E₁=K*q₁/d₁²=9*10⁹*4*10⁻⁹/1²=36N/C

Components (x-y) of the field due to q1:

E₁x=E₁*cosα = 36*(0.6/1)  = 36*(0.6) = 21.6 N/C

E₁y=E₁*sinα  =  36*(0.8/1) = 36*(0.8) =28.8 N/C

Calculation of the electric field at the origin of x-y coordinates due to the charge q₂

E₂=K*q₂/d₂² = -9*10⁹*6*10⁻⁹/0.6² = -150 N/C

Calculation of the electric field components at the origin of x-y coordinates

E₀ is the electric field at the origin of x-y coordinates (x=0,y=0)

E₀x= E₁x+E₂= 21.6-150 = -128.4 N/C

E₀y= E₁y = 28.8 N/C

A )Magnitude of the net electric field at the origin due q₁ and q₂

E_{o} =\sqrt{128.4^{2}+28.8^{2}  }

E₀= 131.6 N/C

B) Direction of the net electric field at the origin due q₁ and q₂

\beta =tanx{-1} \frac{E_{oy} }{Eox}

\beta =tan^{-1} \frac{28.8}{128.4}

β=3.91°

6 0
3 years ago
Other questions:
  • LOOK AT THE PICTURE!! 3 <br> Please answer properly
    9·2 answers
  • What velocity vector will move you 200 miles east in 4 hours traveling at a constant speed?
    6·1 answer
  • a force of magnitude 30 n stretches a spring 0.83 m from equilibrium. what is the value of the spring constant?
    10·1 answer
  • Explain two ways that humans use electromagnetic waves.
    15·1 answer
  • __________ receptors detect presence of acids in substances, whereas __________ receptors detect sodium in substances. A. Sour .
    11·2 answers
  • A radio has a 1.3 A current. If it has a resistance of 35 Ω, what is the potential difference?
    6·2 answers
  • Why is mercury not suitable as the liquid in the U-tube? (the relationship between density of the liquid and the pressure in the
    10·1 answer
  • An elephant pushes with 2000 N on a load of trees. It then pushes these trees for 150 m. How much work did the elephant d
    6·1 answer
  • Please help me:)
    9·1 answer
  • Which factors are always part of linear motion?
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!