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RideAnS [48]
3 years ago
7

Which of the following molecules found within the cell membrane is thought to be involved in cell self-recognition? a. carbohydr

ates b. lipids c. proteins d. cholesterol
Physics
1 answer:
Nadusha1986 [10]3 years ago
6 0

Answer:

Lipids

Explanation:

Membrane mostly considered largely of lipid  bilayer. It is the double called phospholipids. These glycolipids contains the chain of fatty acids. These fatty acids determines that whether the sheet of membrane is formed around the vesicles or not.

Lipids that provide a liquid to the membrane cells. The consistency of liquid appears as the light oil. It consists of fatty acid chain that includes many fatty acid molecules for example oxygen that permeate from the membrane. These fatty acids repels large molecules fatty acids such as sugar, electrical charged ions etc.

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The distance traveled by a wave during a single period is
White raven [17]
I think it's wavelength
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7 0
3 years ago
In 40 words or fewer, summarize the connection between kinetic and thermal energy.<br> PLEASE REPLY
xz_007 [3.2K]

Answer:

Explanation:

kenetic is made for thermal things

8 0
3 years ago
Which object had more potential energy when it was lifted to a distance of 1000 centimeters? Show your calculation.
RSB [31]

Explanation:

We Know That

POTENTIAL ENERGY= MASS*g*HEIGHT

When the objects are lifted to same height then the object with heavier mass would have the highest potential energy

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5 0
2 years ago
A 125-kg astronaut (including space suit) acquires a speed of 2.50 m/s by pushing off with her legs from a 1900-kg space capsule
ryzh [129]

(a) 0.165 m/s

The total initial momentum of the astronaut+capsule system is zero (assuming they are both at rest, if we use the reference frame of the capsule):

p_i = 0

The final total momentum is instead:

p_f = m_a v_a + m_c v_c

where

m_a = 125 kg is the mass of the astronaut

v_a = 2.50 m/s is the velocity of the astronaut

m_c = 1900 kg is the mass of the capsule

v_c is the velocity of the capsule

Since the total momentum must be conserved, we have

p_i = p_f = 0

so

m_a v_a + m_c v_c=0

Solving the equation for v_c, we find

v_c = - \frac{m_a v_a}{m_c}=-\frac{(125 kg)(2.50 m/s)}{1900 kg}=-0.165 m/s

(negative direction means opposite to the astronaut)

So, the change in speed of the capsule is 0.165 m/s.

(b) 520.8 N

We can calculate the average force exerted by the capsule on the man by using the impulse theorem, which states that the product between the average force and the time of the collision is equal to the change in momentum of the astronaut:

F \Delta t = \Delta p

The change in momentum of the astronaut is

\Delta p= m\Delta v = (125 kg)(2.50 m/s)=312.5 kg m/s

And the duration of the push is

\Delta t = 0.600 s

So re-arranging the equation we find the average force exerted by the capsule on the astronaut:

F=\frac{\Delta p}{\Delta t}=\frac{312.5 kg m/s}{0.600 s}=520.8 N

And according to Newton's third law, the astronaut exerts an equal and opposite force on the capsule.

(c) 25.9 J, 390.6 J

The kinetic energy of an object is given by:

K=\frac{1}{2}mv^2

where

m is the mass

v is the speed

For the astronaut, m = 125 kg and v = 2.50 m/s, so its kinetic energy is

K=\frac{1}{2}(125 kg)(2.50 m/s)^2=390.6 J

For the capsule, m = 1900 kg and v = 0.165 m/s, so its kinetic energy is

K=\frac{1}{2}(1900 kg)(0.165 m/s)^2=25.9 J

3 0
3 years ago
A mass of 25kg is moving and is stopped in 1.2 seconds with an acceleration of 1.0 m/s squared what is the force on the mass?
Phantasy [73]
F=ma therefore 25kg*1.0m/s^2=25N force on the mass
6 0
3 years ago
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