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4vir4ik [10]
3 years ago
5

a person walks 750m due north then 250 m due east of the entire walk takes 12 min find the person average velocity​

Physics
1 answer:
Virty [35]3 years ago
6 0

Answer:

v = 1.098 m/s

Explanation:

Given that,

A person walks 750m due north then 250 m due east of the entire walk takes 12 min.

We need to find the average velocity of the person.

Displacement,

d=\sqrt{750^2+250^2} \\\\d=790.56\ m

Average velocity = displacement/time

v=\dfrac{790.56\ m}{12\times 60\ s}\\\\v=1.098\ m/s

So, the average velocity of the person is 1.098 m/s.

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nadya68 [22]
Acceleration = change in velocity/time
= 40/5
=8m/s^2
6 0
3 years ago
Two objects are thrown vertically upward, first one, and then, a bit later, the other. Is it (a) possible or (b) impossible that
Studentka2010 [4]

Answer:

No, it is impossible

Explanation:

Kinematics equation:

Vf^{2} =Vo^{2} -2gy

if height is maximum:

y=H and Vf=0

so:

<h3>Vo^{2} =2gH</h3><h3>H=Vo^{2} /2g</h3>

Analysis: From the last equation we see that the maximum height depends ONLY on the initial speed. This means that if both objects reach the same maximum height, then they necessarily need to have the SAME initial velocity. If they have the same initial velocity and in order to reach the maximum height at the SAME time the only way is that they are released at the SAME TIME.

5 0
3 years ago
When you lift a bowling ball with a force of 61.1 N, the ball accelerates upward with an acceleration a. If you lift with a forc
gtnhenbr [62]

Answer:

the weight of the ball is w = 51.94 N ( mass = 5.3 kg)

Explanation:

Following Newton's second law:

net force = mass * acceleration = weight/gravity * acceleration

then denoting 1 and 2 as the first and second lift

F₁ - w= w/g *a₁

F₂ -w = w/g *a₂ = w/g * 2.07a

dividing both equations

(F₂- w)/(F₁ -w)= 2.07

(F₂- w) = 2.07 * (F₁ -w)

1.07*w = 2.07*F₁ - F₂

w = (2.07*F₁ - F₂ )/ 1.07

replacing values

w = (2.07*61.1 N - 70.9 N )/ 1.07  = 51.94 N

then the weight of the ball is w = 51.94 N ( mass = 5.3 kg)

7 0
2 years ago
is this true or false? an object with a mass of 9.0kg has an acceleration of 3m/s2. the force acting on it is 3N
ludmilkaskok [199]

The answer is "False". The force acting on the object is 27 N.

According to Newton's second law, when a force <em>F</em> acts on am object of mass <em>m</em>, it produces an acceleration <em>a</em>. The force is given by the expression,

F=ma

Thus, if the body has a mass of 9.0 kg and if it has an acceleration of 3 m/s², then, on substituting the values in the equation for force,

F=ma\\ =(9.0kg)(3m/s^2)\\ =27N

Thus, it can be seen that the force acting on the body is 27 N and not 3 N as is mentioned in the statement. Hence the statement is false.

5 0
3 years ago
What is the most likely outcome of increasing the number of slits per unit distance on a diffraction grating?1) lines become nar
Nina [5.8K]

It's important to know that diffraction gratings can be identified by the number of lines they have per centimeter. Often, more lines per centimeter is more useful because the images separation is greater when this happens. That is, the distance between lines increases.

<h2>Therefore, the answer is 2.</h2>
8 0
1 year ago
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