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4vir4ik [10]
3 years ago
5

a person walks 750m due north then 250 m due east of the entire walk takes 12 min find the person average velocity​

Physics
1 answer:
Virty [35]3 years ago
6 0

Answer:

v = 1.098 m/s

Explanation:

Given that,

A person walks 750m due north then 250 m due east of the entire walk takes 12 min.

We need to find the average velocity of the person.

Displacement,

d=\sqrt{750^2+250^2} \\\\d=790.56\ m

Average velocity = displacement/time

v=\dfrac{790.56\ m}{12\times 60\ s}\\\\v=1.098\ m/s

So, the average velocity of the person is 1.098 m/s.

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A runner completes a 10 km run in about 45 minutes. What was the runner’s speed in km/h?
OlgaM077 [116]

Answer: 12.5 km/s

I don't really know how to explain this, but here is your answer.

5 0
3 years ago
A woman exerts a constant horizontal force on a large box. As a result, the box moves across a horizontal floor at a constant sp
d1i1m1o1n [39]

Answer:C

Explanation:

When a constant horizontal force is applied to the box, box started moving in the horizontal direction such that it moves with constant velocity v_0

Constant velocity implies that net force on the box is zero

i.e. there must be an opposing force which is equal to the applied force and friction force can serve that purpose.

So option c is the correct choice.      

6 0
3 years ago
How long does a car (1000 kg) have a speed of 30 m/s from a rest if the engine power is 10kw
Lemur [1.5K]

Answer: 90.1 s

Explanation:

Use equation for power:

P=F*V

Use eqation for force:

F=ma

F---force

V---velocity

Vr=om/s

V=30m/s

m=1000kg

P=10000W

---------------------------

P=FV

F=P/V

F=10000W/30m/s

F=333.33N

Use equation for force to find accelartaion.

F=ma

a=F/m

a=333.33N/1000kg

a=0.333 m/s²

Use equation for accelaration to find out time:

a=(V-Vs)/t

t=(V-Vs)/a

t=(30m/s)/(0.333m/s²)

t=90.09 s≈90.1 s

------------------------

5 0
3 years ago
What is the acceleration experienced by a car that takes 10s to reach 27m/s from rest
Lerok [7]

|acceleration|  =  (change in speed) / (time for the change)

Change in the car's speed = (27 - 0) = 27 m/s
Time for the change  =  10 sec

|acceleration| = (27 m/s) / (10 s)  =  2.7 m/s² .

That's the magnitude of the car's acceleration.
We don't know anything about its direction.
5 0
3 years ago
Pikes Peak near Denver, Colorado, has an elevation of 14,110 ft. Calculate the pressure at this elevation using three different
kramer

Answer:

a) P = 1240 lb/ft^2

b) P = 1040 lb/ft^2

c) P = 1270 lb/ft^2

Explanation:

Given:

- P_a = 2216.2 lb/ft^2

- β = 0.00357 R/ft

- g = 32.174 ft/s^2

- T_a = 518.7 R

- R = 1716 ft-lb / slug-R

- γ = 0.07647 lb/ft^3

- h = 14,110 ft

Find:

(a) Determine the pressure at this elevation using the standard atmosphere equation.

(b) Determine the pressure assuming the air has a constant specific weight of 0.07647 lb/ft3.

(c) Determine the pressure if the air is assumed to have a constant temperature of 59 oF.

Solution:

- The standard atmospheric equation is expressed as:

                           P = P_a* ( 1 - βh/T_a)^(g / R*β)

                          (g / R*β) = 32.174 / 1716*0.0035 = 5.252

                            P = 2116.2*(1 - 0.0035*14,110/518.7)^5.252

                            P = 1240 lb/ft^2

- The air density method which is expressed as:

                            P = P_a - γ*h

                            P = 2116.2 - 0.07647*14,110

                            P = 1040 lb/ft^2

- Using constant temperature ideal gas approximation:

                            P = P_a* e^ ( -g*h / R*T_a )

                            P = 2116.2* e^ ( -32.174*14110 / 1716*518.7 )

                            P = 1270 lb/ft^2

6 0
3 years ago
Read 2 more answers
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