Answer:
x = 8.0
Step-by-step explanation:
sin theta = opposite/ hypotenuse
sin 53 = x/10
Multiply by 10 on each side
10 sin 53= x
7.9863551 =x
Rounding to the nearest tenth
8.0 =x
There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.
You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.
-x^6 + 3x^4 + 4x^2
-x^2(x^4 - 3x^2 - 4)
Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.
-x^2(x^4 - 3x^2 - 4)
-x^2(x^2 - 4)(x^2 + 1)
Now we can use the factors of two perfect squares rule to factor the middle parenthesis.
-x^2(x^2 - 4)(x^2 + 1)
-x^2(x - 2)(x + 2)(x^2 + 1)
We would also want to split the term in the front.
-x^2(x - 2)(x + 2)(x^2 + 1)
(x)(-x)(x - 2)(x + 2)(x^2 + 1)
Now we would set each portion equal to 0 and solve.
First root
x = 0 ---> no work needed
Second root
-x = 0 ---> divide by -1
x = 0
Third root
x - 2 = 0
x = 2
Forth root
x + 2 = 0
x = -2
Fifth and Sixth roots
x^2 + 1 = 0
x^2 = -1
x = +/- 
x = +/- i
Answer:
a
Step-by-step explanation:
sec (thita) = squrt (5)
squaring on both sides:
sec^2 (thita) = 5 - equation 1
1 + tan^2 (thita) = 5
tan^2 (thita) = 4
tan (thita) = 2.
= tan (thita) - squrt(5)sin(thita)
= 2 - squrt(5) x 2/ squrt(5)
= 0
from eqn - 1
sec(thita) = squrt(5)
cos(thita) = 1/ squrt(5)
sin(thita) = squrt ( 1- 1/(squrt (5))^2)
sin(thita) = 2/ squrt(5) .
Answer:
8/30
Step-by-step explanation:
Dividing fractions is almost the same as multiplying to do it you just have to flip the second fraction and change the division sign to a multiplication sign like this,
2/10×4/3
then from there, you have to multiply the top numbers and the bottom numbers
2×4=8
10×3=30
then put them together
8/30