Answer: 20 fragments
Explanation:
This particular restriction enzyme has a 4 bp (base pair) recognition sequence therefore it will cleave once every 4ⁿ bases where n indicates the number pf bases in the recognition sequence.
- The recognition sequence is 4 bp therefore this restriction enzyme cleaves once every 4⁴ = 256 bases. This is the length of the restriction fragment.
- Calculate the number of fragments by dividing the total number of bases ( where you assume equal frequency of bases ie. A+T = C+G) by the length of the restriction base.
- therefore 5000bp/256bp = <u>19,53</u> now this number ca n be rounded up to 20.
- The expected number of fragments on the electrophoresis gel will be 20 fragments.
B. ATP production begins with glucose
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The answer is True.
Amoebas, Paramecia, and Euglenas are all types of protist that can reproduce asexually through binary fission. This is the most common form of reproduction in prokaryotes. The reproduction occurs in a single cell. The cell divides into two nearly equal sized along with its genetic material.
