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attashe74 [19]
3 years ago
6

Question 16

Mathematics
1 answer:
kogti [31]3 years ago
5 0

Answer:

15%

Step-by-step explanation:

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a party rental company has chairs and tables for rent the total cost to rent 2 chairs and 3 tables is 29 dollars the total cost
melomori [17]

Answer:

78

Step-by-step explanation:

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3 years ago
Read 2 more answers
1. Write an equivalent<br> ratio by multiplying:<br> 1<br> -<br><br> 4
ahrayia [7]

Answer:

2 4

- _

8 16

Step-by-step explanation:

1 2

- X -

4 2

Or

1. 4

- X -

4. 4

7 0
3 years ago
The amphitheater has two types of tickets available, reserved seats and lawn seats. The maximum capacity of the venue is 20,000
Tema [17]

Let the number of reserved tickets = x

Let the number of lawn seats = y

Constraint functions:

Maximum capacity means x+y\leq 20000

For concert to be held x+y\geq 5000

lawn seats\leq reserved means y\leq x

Objective functions :

Maximum profit equation p = 65x +40y

Intersection points :

(10000,10000) (20000,0)(2500,2500)(5000,0)

p at (10000,10000) = 65(10000) + 40(10000) = $1050000

p at (20000,0) = 65(20000) + 40(0) = $1300000

p at (2500,2500) = 65(2500) + 40(2500) = $262500

p at (5000,0) = 65(5000) + 40(0) =  $325000

Hence maximum profit occurs when all 20000 reserved seats are sold and the profit is $1300000

Please find attached the graph of it.

8 0
4 years ago
Find the volume of the following cylinder using its net.
lord [1]

Answer:

226.08 yd 3

Step-by-step explanation:

3 0
3 years ago
The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of m
UkoKoshka [18]

Answer:

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

X \sim N(14.7,3.7)  

Where \mu=14.7 and \sigma=3.7

Since the distribution of X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we have;

\mu_{\bar X}= 14.70

\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59

Step-by-step explanation:

Assuming this question: The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of 14.7 minutes and a standard deviation of 3.7 minutes. Let R be the mean delivery time for a random sample of 40 orders at this restaurant. Calculate the mean and standard deviation of \bar X Round your answers to two decimal places.

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

X \sim N(14.7,3.7)  

Where \mu=14.7 and \sigma=3.7

Since the distribution of X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we have;

\mu_{\bar X}= 14.70

\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59

4 0
3 years ago
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