Answer:
381 different types of pizza (assuming you can choose from 1 to 7 ingredients)
Step-by-step explanation:
We are going to assume that you can order your pizza with 1 to 7 ingredients.
- If you want to choose 1 ingredient out of 7 you have 7 ways to do so.
- If you want to choose 2 ingredients out of 7 you have C₇,₂= 21 ways to do so
- If you want to choose 3 ingredients out of 7 you have C₇,₃= 35 ways to do so
- If you want to choose 4 ingredients out of 7 you have C₇,₄= 35 ways to do so
- If you want to choose 5 ingredients out of 7 you have C₇,₅= 21 ways to do so
- If you want to choose 6 ingredients out of 7 you have C₇,₆= 7 ways to do so
- If you want to choose 7 ingredients out of 7 you have C₇,₇= 1 ways to do so
So, in total you have 7 + 21 + 35 + 35 + 21 +7 + 1 = 127 ways of selecting ingredients.
But then you have 3 different options to order cheese, so you can combine each one of these 127 ways of selecting ingredients with a single, double or triple cheese in the crust.
Therefore you have 127 x 3 = 381 ways of combining your ingredients with the cheese crust.
Therefore, there are 381 different types of pizza.
Answer: x=4 ; y=<u> -4</u>
3
Step-by-step explanation:
2x + y = -4
.(-3)
2x + 3y = 4
-6x-3y=12
<u>2x + 3y = 4</u>
4x=16
x= <u>16</u>
4
x=4
2x + 3y = 4
2.4+3y=4
8+3y=4
3y= -8+4
y=<u> -4</u>
3
It would be much easier for me to help you pick the correct equation
if you would let me see the list of choices.
Since I can't see any of the choices, I'll just make up a few equations
that have the ordered pair (24, 6) as a solution:
Y = 0.25 x
Y = x - 18
Y = 0.5 x - 6
Y = 0.1 x + 3.6
Answer:
{(0, 0), (1, 2), (2, 4), (3, 4)
Step-by-step explanation:
the x in the ordered pair is not suppose to repeat, clearly this doesn't