Ask question

Ask question

All categories

3 years ago

10

Divide x^5/8 by x^1/4

1 answer:

IrinaVladis [17]3 years ago

8 0

The correct answer is: [D]: " x^(⅜) " .
_____________________________________________
Explanation:
_____________________________________________
x^(⅝) <span>÷ </span>x^(¼) = x^[ (⅝) - (¼) ] = x^[ (⅝) - (2/8) ] = x^(⅜) .
_____________________________________________

You might be interested in

Equalizing fractions

dexar [7]

What is the question?

7 0

3 years ago

A radioactive isotope has a rate of decay of 84%. that is, every day,

Paul [167]

The half life of the radioactive isotope to the nearest tenth is 0.83 days.

<h3>What is rate of radioactive decay?</h3>

The rate of radioactive decay is the rate at which a radioactive isotope is disintegrated. The half life is the time taken for half of the original amount of radioactive isotope to remain.

Given that;

t/12 = 0.693/k

Where;

t1/2 - half life

k =decay constant

t/12 = 0.693/0.84

t/12 = 0.83 days

Learn more about half life:brainly.com/question/24710827

#SPJ4

7 0

2 years ago

A ball is thrown into the air. The path it takes is modeled by the equation: -3t+24t = h, where t is the time in seconds and h i

astra-53 [7]

Given:

The given equation is:

$-3t^2+24t=h$

Where, t is the time in seconds and h is the height of the ball above the ground, measured in feet.

To find:

The inequality to model when the height of the ball is at least 36 feet above the ground. Then find time taken by ball to reach at or above 36 feet.

Solution:

We have,

$-3t^2+24t=h$

The height of the ball is at least 36 feet above the ground. It means $h\geq 36$ .

$-3t^2+24t\geq 36$

$-3t^2+24t-36\geq 0$

$-3(t^2-8t+12)\geq 0$

Splitting the middle term, we get

$-3(t^2-6t-2t+12)\geq 0$

$-3(t(t-6)-2(t-6))\geq 0$

$-3(t-2)(t-6)\geq 0$

The critical points are:

$-3(t-2)(t-6)=0$

$t=2,6$

These two points divide the number line in 3 intervals $(-\infty,2),(2,6),(6,\infty)$ .

Intervals Check point $-3(t-2)(t-6)\geq 0$ Result

$(-\infty,2)$ 0 $(-)(-)(-)=(-)$ False

$(2,6)$ 4 $(-)(+)(-)=+>0$ True

$(6,\infty)$ 8 $(-)(+)(+)=(-)$ False

The inequality is true for (2,6) and the sign of inequality is $\geq$ . So, the ball is above 36 feet between 2 to 6 seconds.

$6-2=4$

Therefore, the required inequality is $-3t^2+24t\geq 36$ and the ball is 36 feet above for 4 seconds.

3 0

3 years ago

Need help pls asap. 40 points

tia_tia [17]

Answer:

8.04

Step-by-step explanation:

Solution 1

x= r- 4.5= 25.2/2 - 4.5= 8.1

Solution 2

x= √(25.2/2)² - 9.7²= √64.67= 8.04

refer to attachment

6 0

3 years ago

WhO ElSe Is BoReDdDdD

egoroff_w [7]

STAN TXT AND STREAM IF BORED

3 0

3 years ago

Read 2 more answers