Question

A shopper pushes a cart 50 m south down one aisle and then turns 90.0° west and moves 23 m. He then makes another 90.0° turn and moves 14 m. (a) What is the largest possible displacement of the shopper? m ° counterclockwise from west (b) What is the smallest possible displacement of the shopper? m ° counterclockwise from west

Answer 1

Answer:

Step-by-step explanation:

Given

Shopper pushes a cart 50 m south down then turns 90 ^{\circ}  west and moves 23 m.

he then makes $90^{\circ}$ turn and moves 14 m

(a)Largest possible displacement is when he turns towards south

Net displacement$=\sqrt{64^2+23^2}=68.0 m$

(b)Smallest displacement when he turns towards north

$=\sqrt{36^2+23^2}$

$=\sqrt{1825}=42.72 m$