Answer:
250π m³
Step-by-step explanation:
I took the quiz.
Answer:
4th term = 28
5th term = 37
6th term = 45
Step-by-step explanation:
f(n + 1) = f(n) + 8
f(1) = 5
f(1 + 1) = f(1) + 8 = 5+8 = 13
f(2) = 13
f(2 + 1) = f(2) + 8 = 13+8 = 21
Thus, series is 5, 13, 21......
In arithmetic series
Nth term is given by
n th term = a + (n-1)d
where a is the first term
and d is the common difference.
common difference d = nth term - (n-1)th term
For this series
a = 5
lets take nth term as 2nd term and 1st term as (n-1)th term
d = 13-5 = 8
n th term = a + (n-1)d
using the formula for nth term
4th term = 5 + (4-1)8 = 29
5th term = 5 + (5-1) 8= 37
6th term = 5+ (6-1)8 = 45
Thus, 4th term = 28
5th term = 37
6th term = 45
Note this, problem can be solved using f(n + 1) = f(n) + 8 by putting n = 3,4,5 as well but for learning concept of arithmetic series, i have used above process. Hope it helps.
Answer:
That is 7.
Step-by-step explanation:
112 = 2*2*2*2*7
So the smallest number is 7.
2*2*2*2*7*7 is a square number.
I think it’s -3 because I’m guessing you have to times the 4x with the number inside the parenthesis so it would be 4x-12x = 23 and 4-12 is -8 = 23 and 23 divided by -8 is -3
Hey Meri!
x represents the numbers of gallons of gas in the vehicle.
The values x can represent is called our domain.
x can not take on negative values,
it wouldn't make sense to have a negative amount of gas in the car, right?
So the lower limit on our domain is zero.
The car can hold up to 17 gallons of gas,
that should make it clear what the upper limit on our domain is.
The range is the distance traveled on these gallons of gas.
If zero gallons of gas are put into the car,
then no distance will be traveled.
So the low end of our range will be zero.
If 17 gallons of gas are put into the car,
then what distance can the vehicle travel?
Use your function to determine the upper end of your range.