Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
Answer:
560 cubes
Step-by-step explanation:
width: 8 cubes
length: 10 cubes
height: 7 cubes
volume: 8*10*7=560
divided l, w, and h by 1/3 to get them in cubes
Answer:
Step-by-step explanation:
y = 4x + 1
Slope of line = 4
Slope of perpendicular to line = -¼
Point-slope equation for line of slope -¼ that passes through (12, -7):
y+7= -¼(x-12)
Answer:
-16
Step-by-step explanation:
-32.3 - (-16.3).
we know:
-*- =+
-32.3 + 16.3
-16