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andrezito [222]
3 years ago
12

Which of the following sets of numbers could not represent the three sides of a right triangle?

Mathematics
2 answers:
Andrej [43]3 years ago
7 0

Answer:

12, 35, 37 , I think..

Step-by-step explanation:

ELEN [110]3 years ago
4 0

Answer:

{29, 45, 53}

Step-by-step explanation:

12^2+35^2=37^2

144+1225=1369

√1369=37

9^2+40^2=41^2

81+1600=1681

√1681=41

32^2+60^2=68^2

1024+3600=4624

√4624=68

29^2+45^2≠53^2

841+2025=2866

√2866=53.54

√2866≠53

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Answer:

Maggie bought 77 pencil sharpeners

$46.20 divided by .60 = 77

Step-by-step explanation:

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A = LW

A = 28 × 7.1

A = 198.8

The correct answer is A.
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How do I solve: 2 sin (2x) - 2 sin x + 2√3 cos x - √3 = 0
ziro4ka [17]

Answer:

\displaystyle x = \frac{\pi}{3} +k\, \pi or \displaystyle x =- \frac{\pi}{3} +2\,k\, \pi, where k is an integer.

There are three such angles between 0 and 2\pi: \displaystyle \frac{\pi}{3}, \displaystyle \frac{2\, \pi}{3}, and \displaystyle \frac{4\,\pi}{3}.

Step-by-step explanation:

By the double angle identity of sines:

\sin(2\, x) = 2\, \sin x \cdot \cos x.

Rewrite the original equation with this identity:

2\, (2\, \sin x \cdot \cos x) - 2\, \sin x + 2\sqrt{3}\, \cos x - \sqrt{3} = 0.

Note, that 2\, (2\, \sin x \cdot \cos x) and (-2\, \sin x) share the common factor (2\, \sin x). On the other hand, 2\sqrt{3}\, \cos x and (-\sqrt{3}) share the common factor \sqrt[3}. Combine these terms pairwise using the two common factors:

(2\, \sin x) \cdot (2\, \cos x - 1) + \left(\sqrt{3}\right)\, (2\, \cos x - 1) = 0.

Note the new common factor (2\, \cos x - 1). Therefore:

\left(2\, \sin x + \sqrt{3}\right) \cdot (2\, \cos x - 1) = 0.

This equation holds as long as either \left(2\, \sin x + \sqrt{3}\right) or (2\, \cos x - 1) is zero. Let k be an integer. Accordingly:

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Any x that fits into at least one of these patterns will satisfy the equation. These pattern can be further combined:

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7 0
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Write a paragraph comparing the two classes' semester grades. Be sure to compare the extremes, the quartiles, the medians, and t
NISA [10]

Answer:

Class second have higher score and have greater spread.

Step-by-step explanation:

For first box plot

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First class has greater median.

second class has greater third quartile.

Second class has greater Maximum value.  It means second class have higher score than first class.

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Second class has greater inter quartile range.  It means the data of second class has greater spread.

Therefore, the class second have higher score and have greater spread.

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Answer:

x = -2

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