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dexar [7]
2 years ago
9

What is the base of a quantity declining at a rate of 8% per year

Mathematics
1 answer:
mash [69]2 years ago
6 0
476190.47
There you go
Hope it helps
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The function, f(t) = 100.000 describes the number of people who will become infected with a virus in t weeks. Approximately how
Alchen [17]

Answer:

100,000

Step-by-step explanation:

We are given a function: f(t) = 100,000, where,

f(t) is a function that tells us about the number of people who will be infected in t weeks. Here t that is number of week is the independent variable and f(t) is the dependent variable.

We observe that f(t) is a constant function that is it does not depend on the value of t. Whatever may be the value of t it will always take the constant value of 100,000.

So, after ten weeks that is we put t = 10, we get,

f(10) = 100,000

Thus, after 10 weeks 100,000 people will be infected.

5 0
3 years ago
What fraction of one hour (60 minutes) is represented by the following numbers of minutes? Simplify each fraction whenever possi
Alenkasestr [34]

Answer:

\frac{1}{4}

\frac{1}{3}

8 0
2 years ago
What is the answer to x + 23 = 15
Roman55 [17]

Answer:

-8

Step-by-step explanation:

1. x + 23 = 15

2. x + 23 = 15

-23 -23

3. x = -8

5 0
3 years ago
Read 2 more answers
Question 1,2, and 3 how do i factor those? Can you show the work and explain how?
DiKsa [7]

1: 3n^{2}+9n+6

notice that each part is divisible by 3

3n^{2} ÷ 3 = n^{2}

9n ÷ 3 = 3n

6 ÷ 3 = 2

so it becomes 3(n^{2} +3n+2)

3n can be rewritten as 2n+n

-you want to rewrite it into two numbers that multiply to the number that's alone (in this case 2)

which would get you

3(n^{2} +2n+n+2)

Now that it's rewritten, you can factor out n + 2 from the equation.

<u><em>the answer is </em></u>

3(n+2)(n+1)

And you can check that by multiplying (n+2)(n+1) which is n^{2} +2n+n+2 and then each of those by 3, which is 3n^{2} +6n+3n+6 or 3n^{2}+9n+6, our origional equation

2: 28+x^{2} -11x

So I rewrote this as x^{2} -11x+28 (it's the same thing, just reordered using the commutative property)

now -11x can be rewritten as -4x-7x

(remember, the two numbers should multiply to equal 28, which is our constant.)

x^{2} -4x-7x+28

now we can factor out x from the first expression and -7 from the second

x(x-4)-7(x-4)

and lastly you factor out x-4,

<u><em>which would give you</em></u>

(x-4)(x-7)

Make sure to check your work and make sure it multiplies to x^{2} -11x+28

3: 9x^{2} -12x+4

The first thing I notice when looking at this problem is that both 9 and 4 are perfect squares. Not only that, but they are the squares of 2 and 3, which are products of -12

So if you rewrite 9 as 3^{2} and 4 as 2^{2}, the equation becomes

3^{2} x^{2} -12x+2^{2}

now that 3^{2} x^{2} is ugly so it can be turned into (3x)^{2}

and -12x can be rewritten as -2*3x*2

so our equation now looks like (3x)^2-2*3x*2+2^{2}

There's a rule that says a^{2} -2ab+b^{2} = (a-b)^{2}

In our case, a=3x and b=2

<u><em>so the final answer is</em></u>

(3x-2)^2

5 0
2 years ago
Can someone help me whose good at geometry?
Pavel [41]
Actually I can help you in three of them as the number "3" is not confined between the arrays ND and NE

So:
It would be
angle END
or
angle DNE
or
angle N
6 0
3 years ago
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