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azamat
3 years ago
11

NEED HELP ASAP FOR HOMEWORK!! IF RIGHT WILL MARK BRAINLIEST!!!​

Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
7 0

Answer:

I think its C

Step-by-step explanation:

(3^{3}\\x6^{6})^{-3}=

\frac{1}{1^{3}x6^{6} ^{3}  }

<h2>\frac{1}{1^{3}x6^{6} ^{3}  } </h2>
alexdok [17]3 years ago
4 0

Answer:

It's the 3rd one using the formula a^{-m} = \frac{1}{a^{m} }

Once you follow that step you need to multiply the exponent of 3 and 6 with the exponent outside the parenthesis..... which is why it's the 3rd one.

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Phil has $6.00 he wants to buy creepy erasers that cost $1.05 each .if he buys 5 more they are 0.79 each does he have enough mon
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No, he doesn't it would be 5 cents over the amount of money he has.

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3 years ago
Which graph represents y as a function of x? <br> A) A <br> B) B <br> C) C <br> D) D
Arlecino [84]

Answer:

where is the graph if you can put it i will give you the answer

Step-by-step explanation:

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Find the standard deviation of
Kruka [31]

Answer:

11.5

The sample standard deviation measures the spread of a data distribution of the sample. It is usually used to estimate the population standard deviation

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Doug’s go-kart can go 50 m in 20s. What is its average speed?
Olegator [25]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
How many equivalence relations are there on the set 1, 2, 3]?
Alex787 [66]

Answer:

We need to find how many number of equivalence relations are on the set {1,2,3}

A relation is an equivalence relation if it is reflexive, transitive and symmetric.

equivalence relation R on {1,2,3}

1.For reflexive, it must contain (1,1),(2,2),(3,3)

2.For transitive, it must satisfy: if (x,y)∈R then (y,x)∈R

3. For symmetric, it must satisfy: if (x,y)∈R,(y,z)∈R then (x,z)∈R

Since (1,1),(2,2),(3,3) must be there is R, (1,2),(2,1),(2,3),(3,2),(1,3),(3,1). By symmetry,

we just need to count the number of ways in which we can use the pairs (1,2),(2,3),(1,3) to construct equivalence relations.

This is because if (1,2) is in the relation then (2,1) must be there in the relation.

the relation will be an equivalence relation if we use none of these pairs (1,2),(2,3),(1,3) . There is only one such relation: {(1,1),(2,2),(3,3)}

we can have three possible equivalence relations:

{(1,1),(2,2),(3,3),(1,2),(2,1)}

{(1,1),(2,2),(3,3),(1,3),(3,1)}

{(1,1),(2,2),(3,3),(2,3),(3,2)}

6 0
4 years ago
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