Question

Find all real numbers $s$ such that $-2(s - 7) > 4s + 8$. Give your answer in interval notation.

Answer 1

Answer:

$s\in (-\infty,1)$

Step-by-step explanation:

Solve the inequality $-2(s - 7) > 4s + 8$

Use distributive property:

$-2s+14>4s+8$

Subtract 4s:

$-2s+14-4s>4s+8-4s\\ \\-6s+14>8$

Subtract 14:

$-6s+14-14>8-14\\ \\-6s>-6$

Divide by -6 (do not forget to change sign, because division by negative number changes the sign):

$s$